0

我有这张桌子：

code |  Seq  | incr | Bin
------------------------
AQ   |  2701 |  1   | 1  
AQ   |  2702 |  2   | 0  
AQ   |  2703 |  3   | 1  
AQ   |  2704 |  4   | 1  
AQ   |  2705 |  5   | 1  
AQ   |  2706 |  6   | 1  
AQ   |  2707 |  7   | 1  
AQ   |  2708 |  8   | 0  
AQ   |  2709 |  9   | 1  
AQ   |  2710 | 10   | 1  
AQ   |  2711 | 11   | 0  
AQ   |  2712 | 12   | 1

我需要获得连续'1'的最大计数以及结果计数的“Seq”列中第一行和最后一行的值。即：对于书面简化表，最大计数为“5”，从“Seq” = 2703 开始​​，以“Seq” = 2707 结尾

所以我想要一个应该是这样的结果表：

code |  SeqStart  | SeqEnd | Count
----------------------------------
AQ   |    2703    |  2707  |   5  
AR   |    2712    |  2722  |  11

试图解决这个问题我认为

"incr" - ( "Bin" = 0 和 max "incr" 但 < "incr" 行中的 "incr" 值， 对于从 3 到 7 的 "incr" 为 2，对于从 9 到的 "incr" 为 8 10 )

可能是一个很好的数学方法但是（因为我在这里写）我找不到一种方法来为每行减法的正确第二个数字编写工作代码

不幸的是，因为我使用的是 OpenOffice (3.4.1)，所以我被困在 HSQLDB 1.8 如果有人可以帮助我，我真的很感激，感谢阅读

4

2 回答 2

1

我只使用 hsql 1.8 自己找到了解决方案 - 如果其他人可能对此感兴趣，我将发布它：

SELECT "a"."code", ("a"."Seq"-"b"."MaxNum" +1) AS "SeqStart", "a"."Seq" AS "SeqEnd", "b"."MaxNum" AS "Count" 
FROM 
    (SELECT DISTINCT "x"."code", "x"."Seq", "x"."incr", "x"."Bin", "y"."incr1", CASE WHEN "x"."Bin" = 1 THEN ("x"."incr"-"y"."incr1") ELSE '0' END AS "Num" 
    FROM "MyTable" AS "x" 
    LEFT JOIN 
    (SELECT "code", "incr", MAX("incr1") AS "incr1" 
    FROM 
        (SELECT "a"."code", "a"."incr", "b"."incr" AS "incr1" 
        FROM "MyTable" AS "a", "MyTable" AS "b" 
        WHERE ("b"."incr" BETWEEN '1' AND ("a"."incr" -1)) AND "b"."Bin" = 0) 
    GROUP BY "code", "incr") AS "y" 
    ON "y"."code" = "x"."code" AND "y"."incr" = "x"."incr") AS "a" 
INNER JOIN 
    (SELECT "code", MAX("Num") AS "MaxNum" 
    FROM 
        (SELECT DISTINCT "x"."code", "x"."Seq", "x"."incr", "x"."Bin", "y"."incr1", CASE WHEN "x"."Bin" = 1 THEN ("x"."incr"-"y"."incr1") ELSE '0' END AS "Num" 
        FROM "MyTable" AS "x" 
        LEFT JOIN 
        (SELECT "code", "incr", MAX("incr1") AS "incr1" 
        FROM 
            (SELECT "a"."code", "a"."incr", "b"."incr" AS "incr1" 
            FROM "MyTable" AS "a", "MyTable" AS "b" 
            WHERE ("b"."incr" BETWEEN '1' AND ("a"."incr" -1)) AND "b"."Bin" = 0) 
        GROUP BY "code", "incr") AS "y" 
        ON "y"."code" = "x"."code" AND "y"."incr" = "x"."incr") 
    GROUP BY "code") AS "b" 
ON "b"."code" = "a"."code" AND "b"."MaxNum" = "a"."Num"
于 2013-07-02T20:29:40.057 回答
0

我只想添加上面查询的调整版本，它快 15 倍：

SELECT "a"."code", ("a"."Seq"-"b"."MaxNum" +1) AS "SeqStart", "a"."Seq" AS "SeqEnd", "b"."MaxNum" AS "Count" 
FROM 
   (SELECT DISTINCT "x"."code", "x"."Seq", "x"."incr", "x"."Bin", "y"."incr1", CASE WHEN "x"."Bin" = 1 THEN ("x"."incr"-"y"."incr1") ELSE '0' END AS "Num" 
   FROM 
      "MyTable" AS "x" 
   LEFT JOIN 
      (SELECT "code", "incr", MAX("incr1") AS "incr1" 
      FROM 
         (SELECT "a"."code", "a"."incr", "b"."incr" AS "incr1" 
         FROM 
            "MyTable" AS "a" 
         INNER JOIN 
            ( SELECT "code", "incr", "Bin" 
            FROM 
               "MyTable" 
            WHERE "Bin" = 0 ) AS "b" 
         ON "b"."code" = "a"."code" AND ( "b"."incr" BETWEEN '1' AND ( "a"."incr" - 1 ) ) ) 
      GROUP BY "code", "incr") AS "y" 
   ON "y"."code" = "x"."code" AND "y"."incr" = "x"."incr") AS "a" 
INNER JOIN 
   (SELECT "code", MAX("Num") AS "MaxNum" 
   FROM 
      (SELECT DISTINCT "x"."code", "x"."Seq", "x"."incr", "x"."Bin", "y"."incr1", CASE WHEN "x"."Bin" = 1 THEN ("x"."incr"-"y"."incr1") ELSE '0' END AS "Num" 
      FROM 
         "MyTable" AS "x" 
      LEFT JOIN 
      (SELECT "code", "incr", MAX("incr1") AS "incr1" 
      FROM 
         (SELECT "a"."code", "a"."incr", "b"."incr" AS "incr1" 
         FROM 
            "MyTable" AS "a" 
         INNER JOIN 
            ( SELECT "code", "incr", "Bin" 
            FROM 
               "MyTable" 
            WHERE "Bin" = 0 ) AS "b" 
         ON "b"."code" = "a"."code" AND ( "b"."incr" BETWEEN '1' AND ( "a"."incr" - 1 ) ) ) 
      GROUP BY "code", "incr") AS "y" 
   ON "y"."code" = "x"."code" AND "y"."incr" = "x"."incr") 
GROUP BY "code") AS "b" 
ON "b"."code" = "a"."code" AND "b"."MaxNum" = "a"."Num"
于 2013-07-10T20:55:30.853 回答