1

In SQLITE database, if I need table meta details, I can run the following command

C:\sqlite>sqlite3.exe sqlite2.db
SQLite version 3.7.15 2012-12-12 13:36:53
Enter ".help" for instructions
Enter SQL statements terminated with a ";"
sqlite> PRAGMA table_info(forum_forum);
0|id|integer|1||1
1|category_id|integer|0||0
2|name|varchar(100)|1||0
3|description|varchar(200)|1||0
4|locked|bool|1||0

I want to do the similar stuff in sqlalchemy. Can somebody tell me how to do this ?

Solution

from sqlalchemy import *
from sqlalchemy.orm import sessionmaker

db_target = create_engine('sqlite:///C:\\Users\\asit\\workspace\\forum1\\src\\sqlite.db')
session = sessionmaker(db_target, autocommit = True)()

rs = session.execute("PRAGMA table_info(forum_forum)")
for row in rs:
    print '%s %s %s %s %s' % (row['cid'], row['name'], row['type'], row['notnull'], row['pk'])

Output :-

0 id integer 1 1
1 category_id integer 0 0
2 name varchar(100) 1 0
3 description varchar(200) 1 0
4 locked bool 1 0
4

2 回答 2

3

您可以使用 运行任意 SQL 语句session.execute()，包括该 pragma 语句。

该PRAGMA table_info(forum_forum)语句返回一系列行：

>>> res = session.execute("PRAGMA table_info(forum_forum)")
>>> res.keys()
[u'cid', u'name', u'type', u'notnull', u'dflt_value', u'pk']
>>> for row in res:
...     print row
... 
(0, u'id', u'integer', 0, None, 1)
(1, u'category_id', u'integer', 0, None, 0)
(2, u'name', u'varchar(100)', 1, None, 0)
(3, u'description', u'varchar(200)', 1, None, 0)
(4, u'locked', u'bool', 1, None, 0)
于 2013-06-30T11:25:41.007 回答
1

您可以通过以下方式获得很多详细信息

from sqlalchemy import *

db_target = create_engine('sqlite:///C:\\Users\\asit\\workspace\\forum1\\src\\sqlite.db')
target_metadata = MetaData(db_target)
src_master_table = Table('forum_forum', src_metadata, autoload=True )
print src_master_table.columns._data
于 2013-06-30T11:53:43.030 回答