bash - Unix：尝试增加日历年并显示

Question

我有一个 unix 任务，而我的工作不正常。它不像普通的“cal”函数那样格式化。

#!/bin/bash

d=`date '+%Y'`;
$((++d));
calstr=`cal $d`;
echo $calstr;

Answer 1

You don't need the $ in line 2, and you need to wrap the $calstr in double quotes:

#!/bin/bash

d=`date '+%Y'`;
((++d));
calstr=`cal $d`;
echo "$calstr";