1

我有以下 SQL Server 查询，我想移植到 SQLite 3，但它不喜欢它并抱怨语法错误“near (”。

经过一些调试后，问题似乎是 SQLite 不喜欢子查询别名之后的列说明符（我用双星号表示了这些说明符）。

我需要做什么才能使这个查询与 SQLite 一起工作？

    SELECT  rowSet.DBId_0,
        rowSet.TableID_0, 
        CASE WHEN rowSet.HasIdentity_0 != rowSet.HasIdentity_1 THEN 1 ELSE 0 END 'Result'
FROM (
    SELECT * 
    FROM
    (
        SELECT 'Master' AS 'Db', z.[DBId], z.[TableId], MAX(z.[MaxIdentity]) AS 'HasIdentity' 
        FROM
        (
            SELECT so.[DBId], sc.[TableId], MAX(CAST(sc.[Identity] AS TINYINT)) AS MaxIdentity
            FROM syscolumns sc
                JOIN sysobjects so ON sc.[tableid] = so.[id]
            WHERE so.[dbid] = 1
            GROUP BY so.[DBId], sc.[TableId], sc.[Identity]
        ) z
        GROUP BY z.[DBId], z.TableId
    ) **src (Db_0, DBId_0, TableID_0, HasIdentity_0)**
    JOIN 
    (
        SELECT 'Target' AS 'Db', z.[DBId], z.[TableId], MAX(z.[MaxIdentity]) AS 'HasIdentity' 
        FROM
        (
            SELECT so.[DBId], sc.[TableId], MAX(CAST(sc.[Identity] AS TINYINT)) AS MaxIdentity
            FROM target.syscolumns sc
                JOIN target.sysobjects so ON sc.[tableid] = so.[id]
            WHERE so.[dbid] = 1
            GROUP BY so.[DBId], sc.[TableId], sc.[Identity]
        ) z
        GROUP BY z.[DBId], z.TableId
    ) **tar (Db_1, DBId_1, TableID_1, HasIdentity_1)** ON tar.[DBId_1] = src.[DBId_0] AND tar.[TableId_1] = src.[TableId_0]
) rowSet

这是您可以尝试的示例查询：

这有效（在 SQLite 中）：

select col1, col2
from
(
    select 1 as 'col1', 2 as 'col2'
    union
    select 3 as 'col1', 4 as 'col2'
)

这不（在 SQLite 中）：

select col1, col2
from
(
    select 1 as 'col1', 2 as 'col2'
    union
    select 3 as 'col1', 4 as 'col2'
) z (col1, col2)
4

2 回答 2

2

重命名列的标准 SQL 方法是使用列别名，即：

SELECT z.col1, z.col2
FROM
(
    SELECT 1 AS col1, 2 AS col2
    UNION ALL
    SELECT 3,         4
) AS z
于 2013-06-29T21:07:26.110 回答
1

您可以为子查询中的列设置别名，但在表别名中，您不能再次指定别名。在以下查询中，您可以在子查询之外指定表别名，并在内部指定列别名：

select col1, something
from
(
    select 1 as 'col1', 2 as 'something'
    union
    select 3, 4 
) z
于 2013-06-29T21:16:31.023 回答