我想在任何地方长按地图后删除当前标记并在该点重新创建一个新标记。我在长按地图时清除了谷歌地图并创建了新标记,但也显示了前一个标记。
我的代码是:
public class EditLocation extends Fragment {
View v;
Context c;
GoogleMap MAP;
Button back;
int loc;
String lat;
boolean isTapped = true;
public EditLocation(Context c, int location, String latitude) {
// TODO Auto-generated constructor stub
this.c = c;
this.loc = location;
this.lat = latitude;
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
v = inflater.inflate(R.layout.map, container, false);
int status = GooglePlayServicesUtil.isGooglePlayServicesAvailable(c);
if (status != ConnectionResult.SUCCESS) {
int requestCode = 10;
Dialog dialog = GooglePlayServicesUtil.getErrorDialog(status,
(Activity) c, requestCode);
dialog.show();
} else {
FragmentManager myFM = ((FragmentActivity) c)
.getSupportFragmentManager();
final SupportMapFragment myMAPF = (SupportMapFragment) myFM
.findFragmentById(R.id.fragmentmap);
MAP = myMAPF.getMap();
MAP.setMyLocationEnabled(true);
LocationManager locationManager = (LocationManager) c
.getSystemService(Context.LOCATION_SERVICE);
Criteria criteria = new Criteria();
String provider = locationManager.getBestProvider(criteria, true);
final Location location = locationManager
.getLastKnownLocation(provider);
final LatLng currentPosition = new LatLng(location.getLatitude(),
location.getLongitude());
MAP.setOnMapClickListener(new OnMapClickListener() {
@Override
public void onMapClick(LatLng point) {
// TODO Auto-generated method stub
MAP.addMarker(new MarkerOptions()
.position(currentPosition)
.snippet(
"Lat:" + location.getLatitude() + "Lng:"
+ location.getLongitude())
.icon(BitmapDescriptorFactory
.defaultMarker(BitmapDescriptorFactory.HUE_AZURE))
.title("ME"));
Log.e("lat", "" + point);
}
});
MAP.setOnMapLongClickListener(new OnMapLongClickListener() {
@Override
public void onMapLongClick(LatLng point) {
// TODO Auto-generated method stub
// isTapped = false;
MAP.clear();
MAP.addMarker(new MarkerOptions().position(point)
.title(point.toString()));
}
});
}
return v;
}