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如果我只知道设备名称是“\.\PhysicalDrive0”并且上面没有文件系统或卷标，如何从 Windows 中的块设备或原始磁盘获取大小？

我尝试了以下方法：

fd = os.open(r"\.\PhysicalDrive0", os.O_RDONLY)

os.lseek(fd, 0, os.SEEK_END)

它在 Linux 上运行良好，但在 Windows 上总是返回“OSError: [Errno 22] Invalid argument”。

我也尝试了 ctypes.windll.kernel32.GetDiskFreeSpaceExW()，但它似乎只适用于具有文件系统和分配卷标的磁盘。

对原始磁盘或块设备执行此操作的正确方法是什么？

提前致谢。

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2 回答 2

2

使用wmi模块

import wmi
c = wmi.WMI()
[drive] = c.Win32_DiskDrive(Index=0)
print("The disk has %s bytes" % drive.size)
print("Or %s GB" % int(int(drive.size) / 1024**3))

The disk has 320070320640 bytes
Or 298 GB

此代码在 WMI 接口中查询Win32_DiskDriveIndex 等于的对象0（因此只有一个结果且该结果为PHYSICALDRIVE0）。该drive对象有一个名为 的属性size，它是一个包含驱动器大小（以字节为单位）的字符串。

于 2016-11-04T06:03:07.147 回答
0

我有一个解决方案.. 但它并不漂亮。使用磁盘部分。不幸的是，如果需要，它不会为您提供确切的字节大小，但它会为您提供人类可读的字符串。

import tempfile
import subprocess
import re
import os

def query_diskpart(command):
    """Run command script for diskpart.

    Args:
        command(str): String of all commands to run against diskpart
    Returns:
        String of all diskpart standard output
    Size Effects:
        Creates a temporary file(and then deletes it)
        Creates a subprocess to run diskpart
    """
    with tempfile.NamedTemporaryFile(mode='w', delete=False) as temp_handle:
        temp_handle.write(command)
    # The temporary file needs to be closed before opening with diskpart
    diskpart_handle = subprocess.Popen(["diskpart", '/s', temp_handle.name], stdout=subprocess.PIPE)
    output, _ = diskpart_handle.communicate()

    os.remove(temp_handle.name)
    return output

def match_drive_size(diskpart_output, disk_num):
    """Get drive size from diskpart output.

    Args:
        diskpart_output(str): String of diskpart standard output
        disk_num(int): Number of PhysicalDrive to match against
    Returns:
        Human readable size of drive.
    Raises:
        ValueError if drive doesn't exist.
        """

    # Break up gigantic output string
    output_lines = diskpart_output.decode().split(os.linesep)
    # Apply regular expression to every line, but it should only match one
    matches = [re.match(".*Disk %s\s*(.*)" % disk_num, line) for line in output_lines]
    size = None
    for match in matches:
        if match:
            # Get first subgroup (parens above)
            size_line = match.group(1)
            # Split by whitespace
            size_list = re.split("\s*", size_line)
            # Merge numerical value + units
            # ['256', 'GB'] becomes 256GB
            size = ''.join(size_list[1:3])
            break
    else:
        raise ValueError("PHYSICALDRIVE%s does not exist", disk_num)
    return size

def get_drive_size(disk_num):
    """Get Windows Drive size.

    Args:
        disk_num(int): The Physical Drive Number
            e.g. for PHYSICALDRIVE0 put 0
    Returns:
        Human readable string of the drive size
    """
    output = query_diskpart("list disk\n")
    drive_size = match_drive_size(output, disk_num)
    return drive_size

if __name__ == "__main__":
    print(get_drive_size(0))
于 2016-06-21T07:06:35.527 回答