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如果电池电量严重不足,我需要我的应用程序在来电时弹出消息。有没有办法做到这一点(如果可能的话,切断电话)?在网上搜索对我没有多大帮助。

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1 回答 1

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用于在来电期间显示某些内容

 public class IncomingCallReciever extends BroadcastReceiver {

private Context mContext;
private Intent mIntent;

@Override
public void onReceive(Context context, Intent intent) {
    mContext = context;
    mIntent = intent;
    TelephonyManager tm = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
    int events = PhoneStateListener.LISTEN_CALL_STATE;
    tm.listen(phoneStateListener, events);
}

private final PhoneStateListener phoneStateListener = new PhoneStateListener() {
    @Override
    public void onCallStateChanged(int state, String incomingNumber) {
        String callState = "UNKNOWN";
        switch (state) {
        case TelephonyManager.CALL_STATE_IDLE:
            callState = "IDLE";



            break;
        case TelephonyManager.CALL_STATE_RINGING:
            //  write your code display Toast or Dialog







            break;

        }
        Log.i(">>>Broadcast", "onCallStateChanged " + callState);
        super.onCallStateChanged(state, incomingNumber);
    }
};

}

在你的清单文件中声明这种方式

 <receiver android:name=".IncomingCallReciever"
        android:enabled="true">
        <intent-filter>
            <action android:name="android.intent.action.PHONE_STATE"></action>
            <action android:name="android.intent.action.NEW_OUTGOING_CALL" />
        </intent-filter>
    </receiver>

添加关注权限

 <uses-permission android:name="android.permission.READ_PHONE_STATE"/>
于 2013-06-28T18:33:58.907 回答