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我正在尝试按大表中的几列(近 18 000 行)搜索重复的行。问题是查询需要很多时间,我试过这个:

 SELECT * FROM table_name a, table_name b 
 WHERE a.col1 = b.col1 
 AND a.col2 = b.col2 
 AND a.col3 = b.col3
 AND a.col4 = b.col4 
 AND a.id <> b.id

和这个:

SELECT *
FROM table_name 
WHERE col1 IN (
    SELECT col1 
    FROM table_name 
    GROUP BY col1 
    HAVING count(col1) > 1
    )
AND col2 IN (
    SELECT col2
    FROM table_name 
    GROUP BY col2
    HAVING count(col2) > 1
    )
AND col3 IN (
    SELECT col3
    FROM table_name 
    GROUP BY col3
    HAVING count(col3) > 1
    )
AND col4 IN (
    SELECT col4
    FROM table_name 
    GROUP BY col4
    HAVING count(col4) > 1
    )

他们都工作,但太慢了。有任何想法吗?

4

1 回答 1

1

您可以尝试使用一个联合 GROUP BY 语句,例如:

SELECT * FROM table_name
    GROUP BY col1, col2, col3, col4
    HAVING count(*) > 1

至少,它会看起来更干净。

编辑

要将所有结果作为上一列的子集返回:

SELECT *
FROM table_name 
WHERE col4 IN (
  SELECT col4
  FROM table_name 
  WHERE col3 IN (
    SELECT col3
    FROM table_name 
    WHERE col2 IN (
      SELECT col2
      FROM table_name
      WHERE col1 IN (
        SELECT col1
        FROM table_name
        GROUP BY col1
        HAVING count(col1) > 1
        )
      )
    )

从概念上讲,这应该会在更快的执行时间内为您提供所有结果。

于 2013-06-28T15:17:43.333 回答