0

我得到这个 JSON 字符串：

[
{
    "id": 135,
    "date": "2013-08-30 19:00:29",
    "timestamp": "2013-08-30 19:00:29",
    "lat": "54.328274",
    "long": "-2.747215",
    "strap": "annual International Festival of Street Arts",
    "link": "http://dev.website.co.uk//?p=135",
    "title": "Title"
}
]

我确定这是正确的 JSON 语法（在 iOS 应用程序中工作正常），但是在解析为 JSONObject 时它会捕获错误。爪哇：

public static JSONObject getJSONfromURL(String url){

    //initialize
    InputStream is = null;   
    String result = "";   
    JSONObject jArray = null;

    //http post
    try {

        HttpClient httpclient = new DefaultHttpClient();   
        HttpPost httppost = new HttpPost(url);    
        HttpResponse response = httpclient.execute(httppost);
        HttpEntity entity = response.getEntity();

        is = entity.getContent();    

    } catch (Exception e) {
        Log.e("log_tag", "Error in http connection "+e.toString());   
    }
    //convert response to string

    try {

        BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);  
        StringBuilder sb = new StringBuilder();   
        String line = null;

        while ((line = reader.readLine()) != null) {   
            sb.append(line + "\n");
        }

        is.close();
        result=sb.toString();

    } catch (Exception e) {    
        Log.e("log_tag", "Error converting result "+e.toString());
    }
    //try parse the string to a JSON object

    try {
        Log.d("log_tag", "jresult: " + result + "finish");
        jArray = new JSONObject(result);

    } catch (JSONException e) {
        Log.e("log_tag", "Error parsing data "+e.toString());
    }
    return jArray;
}

JSON中的某处有错误吗？

4

3 回答 3

4

[表示一个json数组节点

{代表一个json对象节点

    JSONArray jArray  = new JSONArray(result);
    return jArray;

您也可以有一个尝试块而不是多个。

于 2013-06-28T14:03:14.183 回答
0

它是一个数组，因此您需要执行“new JSONArray()”而不是“new JSONObject()”。

于 2013-06-28T14:03:04.783 回答
0

当 json 字符串以 开头时[，它将被视为JSONArray您需要做的new JSONArray()

于 2013-06-28T14:04:03.103 回答