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关于这个问题，我已经从Java动态生成字符串。每次字符串格式更改，例如字符串格式是

[{"BranchName":"Corporate Office","Date":"08\/03\/2013","SPName":"Pharmacy","SPAmount_5-00%":"100.00","SPVATAmount_5-00%":"15.00","SPOtherCharges_5-00%":"30.00","SPAmount_14-50%":"200.00","SPVATAmount_14-50%":"39.00","SPOtherCharges_14-50%":"71.00","SPColTPA":"100.00","SPColChequeDD":"50.00","SPHdfcCC":"100.00","SPIdbiCC":"100.00","SPColCash":"50.00","Difference":"55.00"},

但是当我使用以下代码转换数组集合时。

var rawData:String = String(event.result); 
var arr:Array = (JSON.decode(rawData) as Array);
var dp:ArrayCollection = new ArrayCollection(arr);

但数组集合顺序更改为默认排序，如 [Branch, Date, Difference,.. ] 。但我想要与字符串格式顺序相同。那么如何防止默认订单。

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1 回答 1

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实际上，您在这里描述的是一组对象（您的示例仅包含一个对象）。在 JSON 解析为数组的过程中，每个对象确实是按照声明的顺序排列的；但在创建的 OBJECTS 中，属性可能不会以相同的顺序列出。

例如：

'[ {"Branch":"Corporate", "Department":"Finance", "Cost":"10000", "Attended":"true"},' +
'{"Branch":"Las Vegas", "Department":"Hospitality", "Cost":"20100", "Attended":"false"},' +
'{"Branch":"San Diego", "Department":"Banking", "Cost":"11023", "Attended":"true"}]'

解析将返回 arr[0] 作为 Corporate 对象， arr[1] 作为 Las Vegas 对象，等等。遍历我得到的属性：

var obj:Object = dp.getItemAt(0);
for (var prop:String in obj) {
    trace(prop + ' is ' + obj[prop]);
}

Department is Finance
Attended is true
Branch is Corporate
Cost is 10000
于 2013-06-28T15:19:22.943 回答