javascript - Short Javascript code snippet involving if / else not being evaluated correctly

Question

For some reason, the evaluator if isEven(n) is giving an error... can you spot an issue with the code?

function isEven(value) {
    //value = Number(value);
    if (value%2 == 0)
        return true;
    else
        return false;
}


function testCondition {

    if isEven(n) {

    }
    else {

    }
}

Answer 1

您的代码中有两个语法错误：

function isEven(value) {
    //value = Number(value);
if (value%2 == 0) // no parens here is allowed so no syntax error
    return true;
else
    return false;
}


function testCondition() {
                   // ^^ missing parens here

  if (isEven(n)) {
  // ^ ------- ^ -- and here

            } 
  else {

       }
}

Answer 2

if isEven(n) {

你缺少括号，所以你会得到一个SyntaxError

if (isEven(n)) {

正如 Frits van Campen 所指出的，您还缺少()after 。testCondition

Answer 3

只是一些小的语法问题，试试这个：

function isEven(value) {
    //value = Number(value);
    if (value%2 == 0){
        return true;
    }else{
        return false;
    }
}


function testCondition() {

    if (isEven(n)) {
        //do something
    } else {
        //do something else
    }
}