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I have set up a table with a column called order. I made sure it is set as INT. I can't seem to get the results to list in order. I currently have 5 rows with numbers 1-5 in a random order in those rows. However, I can't get those rows to go in order. Maybe I am doing this completely wrong, as I am new to MySql. Here is my query

SELECT * FROM faq ORDER BY 'order'
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5 回答 5

3

您应该使用反引号，而不是引号：

SELECT * FROM faq ORDER BY `order`
于 2013-06-27T19:23:15.410 回答
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您需要在 mysql 中使用反引号，而不是引号。

SELECT * FROM faq ORDER BY `order`
于 2013-06-27T19:23:25.753 回答
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你需要：

SELECT * FROM faq ORDER BY `order`

您在示例中使用单引号。MySQL 使用反引号来包装表名、字段名等。在这种情况下，您需要使用反引号，因为order它是 MySQL 中的保留字。

于 2013-06-27T19:23:11.080 回答
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您'order'像字符串一样引用，因此排序将由值order本身（字符串）而不是列完成。将它们改为反引号。

于 2013-06-27T19:23:19.227 回答
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您应该使用 backtik 而不是引号：

SELECT * FROM faq ORDER BY `order`;

参考：http ://dev.mysql.com/doc/refman/5.0/en/identifiers.html

于 2013-06-28T06:26:53.267 回答