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需要为 std::pair 对象提供来自 boost::variant 类型对象的值。你将如何使用其他资源来实现这个想法？下面还有其他方法吗？

    struct aggr_pair_visitor : public ::boost::static_visitor<void>
    {
    public:
        explicit aggr_pair_visitor( column_and_aggregate & pair_ ) : pair(pair_)
        {
        }
        void operator()(column_name_t const & column)
        {
            pair.first = column;
        }
        void operator()(unsigned const & faggr)
        {
            if ( faggr > static_cast<unsigned>(sql_faggregate::SUM) || faggr < static_cast<unsigned>(sql_faggregate::AVG) )
                throw std::runtime_error("Failed to parse aggregate type : Not valid integer");
            else pair.second = static_cast<sql_faggregate>(faggr);
        }
    private:
        column_and_aggregate & pair;
    };
    void apply_col_and_aggr_visitor( column_and_aggregate & col_and_aggr_pair, ::boost::variant< column_name_t, unsigned > const & val )
    {
        aggr_pair_visitor pair_visitor( col_and_aggr_pair );
        ::boost::apply_visitor( pair_visitor, val ); // N.B.!!! Runtime execution of operator()!
    }
    spirit::qi::rule< iterator, column_and_aggregate(), ascii::space_type > agg_pair =
        quoted_string[::boost::bind( &apply_col_and_aggr_visitor, spirit::qi::_val, spirit::qi::_1 )]
        > ':'
        > spirit::int_[::boost::bind( &apply_col_and_aggr_visitor, spirit::qi::_val, spirit::qi::_1 )];
    spirit::qi::rule< iterator, column_and_aggregate_container(), ascii::space_type > aggregates_parser =
          '{'
        > agg_pair[phoenix::push_back(spirit::qi::_val, spirit::qi::_1)] % ',' // N.B.!!! list-redux technic
        > '}';
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1 回答 1

2

好的，乍一看，我认为您只是错过了融合适应std::pair 的能力：

#include <boost/fusion/adapted/std_pair.hpp>
// Or:
#include <boost/fusion/adapted.hpp>

使用它，整个复杂性消失了，不需要任何涉及变体的东西。让我们假设以下类型：

typedef std::string column_name_t;

enum sql_faggregate
{
    SUM,
    // ....
    AVG,
};

typedef std::pair<column_name_t, sql_faggregate> column_and_aggregate;
typedef std::vector<column_and_aggregate> column_and_aggregate_container;

一个简单的语法是：

template <typename It, typename Skipper = qi::space_type>
    struct parser : qi::grammar<It, column_and_aggregate_container(), Skipper>
{
    parser() : parser::base_type(aggregates_parser)
    {
        using namespace qi;
        // using phx::bind; using phx::ref; using phx::val;

        quoted_string = lexeme [ "'" >> *~qi::char_("'") >> "'" ];
        faggr = int_;
        agg_pair = quoted_string > ':' > faggr;
        aggregates_parser = '{' > agg_pair % ',' > '}';
    }

  private:
    qi::rule<It, std::string(), qi::space_type>           quoted_string;
    qi::rule<It, sql_faggregate(), qi::space_type>        faggr;
    qi::rule<It, column_and_aggregate(), qi::space_type>   agg_pair;
    qi::rule<It, column_and_aggregate_container(), qi::space_type> aggregates_parser;
};

您也可以添加输入验证：

faggr %= int_ [ qi::_pass = (qi::_1 >=SUM and qi::_1<=AVG) ];

注意确保%=属性传播。

完整的工作演示

程序代码：

#include <boost/fusion/adapted/std_pair.hpp>
#include <boost/spirit/include/qi.hpp>
// #include <boost/spirit/include/phoenix.hpp>

namespace qi    = boost::spirit::qi;
namespace phx   = boost::phoenix;

typedef std::string column_name_t;

enum sql_faggregate
{
    SUM,
    // ....
    AVG,
};

typedef std::pair<column_name_t, sql_faggregate> column_and_aggregate;
typedef std::vector<column_and_aggregate> column_and_aggregate_container;

template <typename It, typename Skipper = qi::space_type>
    struct parser : qi::grammar<It, column_and_aggregate_container(), Skipper>
{
    parser() : parser::base_type(aggregates_parser)
    {
        using namespace qi;
        // using phx::bind; using phx::ref; using phx::val;

        quoted_string = lexeme [ "'" >> *~qi::char_("'") >> "'" ];
        faggr = int_;
        agg_pair = quoted_string > ':' > faggr;
        aggregates_parser = '{' > agg_pair % ',' > '}';

        BOOST_SPIRIT_DEBUG_NODE(aggregates_parser);
    }

  private:
    qi::rule<It, std::string(), qi::space_type>           quoted_string;
    qi::rule<It, sql_faggregate(), qi::space_type>        faggr;
    qi::rule<It, column_and_aggregate(), qi::space_type>           agg_pair;
    qi::rule<It, column_and_aggregate_container(), qi::space_type> aggregates_parser;
};

bool doParse(const std::string& input)
{
    typedef std::string::const_iterator It;
    auto f(begin(input)), l(end(input));

    parser<It, qi::space_type> p;
    column_and_aggregate_container data;

    try
    {
        bool ok = qi::phrase_parse(f,l,p,qi::space,data);
        if (ok)   
        {
            std::cout << "parse success\n";
            for (auto& pair : data)
                std::cout << "result: '" << pair.first << "' : " << (int) pair.second << "\n";
        }
        else      std::cerr << "parse failed: '" << std::string(f,l) << "'\n";

        if (f!=l) std::cerr << "trailing unparsed: '" << std::string(f,l) << "'\n";
        return ok;
    } catch(const qi::expectation_failure<It>& e)
    {
        std::string frag(e.first, e.last);
        std::cerr << e.what() << "'" << frag << "'\n";
    }

    return false;
}

int main()
{
    bool ok = doParse("{ 'column 1' : 1, 'column 2' : 0, 'column 3' : 1 }");
    return ok? 0 : 255;
}

打印输出：

parse success
result: 'column 1' : 1
result: 'column 2' : 0
result: 'column 3' : 1

PS：如果你想在语义动作中做同样的事情，你可能想这样写：

agg_pair = 
      quoted_string [ phx::bind(&column_and_aggregate::first, _val)  = _1 ]
    > ':'
    > faggr         [ phx::bind(&column_and_aggregate::second, _val) = _1 ];

你会看到你可以把它放在上面的示例中，它的工作原理完全相同。对于这个特定的语法，它只是更冗长，所以我不推荐它:)

于 2013-06-27T16:02:14.403 回答