我们目前正在使用 spring 框架并使用以下 XML:-
<bean id="A" class="com.foo.baar.A" >
<property name="attributes">
<set value-type="com.foo.bar.B">
<ref bean="X" />
<ref bean="Y" />
</set>
</property>
</bean>
<bean id="X" class="com.foo.bar.X" />
<bean id="Y" class="com.foo.bar.Y" />
其中 X 类和 Y 类扩展 B 类
A 类的设置器如下:-
public void setAttributes(List<B> attributes) {
this.attributes = attributes;
}
现在,我必须消除上述 XML,并以编程方式设置 bean,如下所示:-
List<Object> beanRefrences = new ArrayList<Object>();
for(String attribute : attributes) {
Object beanReference = new RuntimeBeanReference(attribute);
beanRefrences.add(beanReference);
}
mutablePropertyValues.add(propertyName, beanRefrences);
使用上面的代码,我收到以下错误:-
nested exception is org.springframework.beans.ConversionNotSupportedException: Failed to convert property value of type 'java.util.ArrayList' to required type 'java.util.List' for property 'attributes';
nested exception is java.lang.IllegalStateException: Cannot convert value of type [org.springframework.beans.factory.config.RuntimeBeanReference] to required type [com.foo.bar.B] for property 'attributes[0]': no matching editors or conversion strategy found
谁能给我指点如何使它正常工作?