jquery - 如何仅过滤数组而不是另一个数组值

Question

我有 2 个数组，在这 2 个中我需要一个数组的输出，它只存在于第 2 个数组中。我试过了，但没有重复；

var x = ["apple","2","3", "4", "3", "x", "M"], y = ["4","5","apple","zoo"];

var z = y.filter(function(){
    return $.inArray(y,x) === -1;
})

console.log(z); i am looking for ["5","zoo"]

我如何过滤这样的..有什么帮助吗？

Answer 1

尝试

var x = ["apple","2","3", "4", "3", "x", "M"], y = ["4","5","apple","zoo"];

var z = $.map(y, function(val, idx){
    return $.inArray(val, x) === -1 ? val : undefined;
})

演示：小提琴

Answer 2

var x = ["apple","2","3", "4", "3", "x", "M"]
,   y = ["4","5","apple","zoo"]
,   result = [];
$.each(x, function (i, v) {
    if ($.inArray(v, y) !== -1) {
        result.push(v);
    }
});
console.log(result);

http://jsfiddle.net/svCys/1