java - 根据起点和终点拆分字符串

Question

如何拆分字符串

'ABCDEFGHIJK'

我知道字符串的起点和终点

Startid endid
1       2
3       5
6       7
8       11

AS
-----

AB
CDE
FG
HIJK

Answer 1

String s = string.subString(startpoint,endpoint);

Answer 2

stringVar.subString(sPoint,ePoint);

确保定期重置 sPoint 和 ePoint 的值

Answer 3

final String toSplit = "ABCDEFGHIJK";

for(final Split split : splits){
    if(null != split){
        if(0 <= split.startid  && split.startid < toSplit.length() && 0 <= split.endid && split.endid < toSplit.length()){
            return toSplit.substring(startid, endid);
        }
    }

    return StringUtils.EMPTY;
}

假设一个包含您的 startid/endid 的类拆分（当然也可以是其他选项）：

class Split {
    public int startid;
    public int endid;

    public Split(int startid, int endid){
        this.startid = startid;
        this.endid = endid;
    }
}

Answer 4

根据您想要的表

String s = string.subString(startpoint-1,endpoint-1);

如果您愿意，可以滥用Point类（最好只创建自己的对象），请执行以下操作

String s = "ABCEDEFG..." // you string
// Create a list of your points (start and end)
List<Point> list = new ArrayList<Point>();
// Add your points
list.add(new Point(1,2));
list.add(new Point(3,5)); //etc
// Then do this to get your substring
String[] splits = new String[list.size()]
int i= 0;
for(Point p: list)
{
   splits[i] = s.substring(p.getX()-1, p.getY()-1)
   i++;
}

Answer 5

public static String getSubString(String myString,int statIndex,int endIndex){
       return myString.substring(statIndex,endIndex);
}