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当 bindValue 为空时，我无法执行动态构建的查询

  • 如果定义了 bindValue 但未使用，则查询不返回任何结果。只要为所有搜索字段输入值，我的查询就可以工作。
  • 我已经尝试过 bindValue 和 bindParam。
  • 目的是仅查询在搜索表单上填写的字段。
  • 我在本地 MySQL 日志中注意到，除非使用所有 bindValue 搜索词，否则该语句将正确准备但不会执行。

这是 mysql.log（填写了所有 3 个字段）：

142 Connect root@localhost on drawings03
142 Prepare SELECT * FROM draw WHERE (`LocationNumber` = ?  && `DrawingNumber` = ?  && `DrawingDate` >= ? )
142 Execute SELECT * FROM draw WHERE (`LocationNumber` = '525'  && `DrawingNumber` = '101'  && `DrawingDate` >= '1950' )
142 Close stmt  
142 Quit

这是一段php：

<?php
  //grabs variables from a search form
$searchTerms['locnum'] = $_GET['locnum'];
$searchTerms['drawnum'] = $_GET['drawnum'];
$searchTerms['projtitle'] = $_GET['projtitle'];
$searchTerms['shttitle'] = $_GET['shttitle'];
$searchTerms['shtnum'] = $_GET['shtnum'];
$searchTerms['discp'] = $_GET['discp'];
$searchTerms['drawdate'] = $_GET['drawdate'];

//Loops through the array
foreach ($searchTerms as $field => $value) {
   if ($value != null && $value != '' && $value != ' ' ) {
// Based on the key name in the array, decide which 
// SQL statement to add to the array to be constructed
      switch ($field) {
         case 'locnum':
            $where[] = "`LocationNumber` = :locnum ";
            break;
         case 'drawnum':
            $where[] = "`DrawingNumber` = :drawnum ";
            break;
         case 'drawdate':
            $where[] = "`DrawingDate` >= :drawdate ";
            break;         
      }              
   }             
}

// Combine WHERE statements into one with && separating each one
$whereSQL = implode(' && ', $where);  
$stmt = $db->prepare("SELECT * FROM draw WHERE (".$whereSQL.")");
$stmt->bindValue(':locnum', $locnum, PDO::PARAM_INT);
$stmt->bindValue(':drawnum', $drawnum, PDO::PARAM_INT);
$stmt->bindValue(':drawdate', $drawdate, PDO::PARAM_STR);

$stmt->execute();
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
$row_count = $stmt->rowCount();
echo "<div class='span12'><b>".$row_count." results"."</b><br>Click <b>to sort</b>.  &nbsp; Right-click link and save-as <b>to save a PDF</b>.</div>";
foreach ($rows as $value) {
   echo $value['LocationNumber']." - ".$value['DrawingNumber']." - ".substr($value['DrawingDate'],0,4)."<br>";
}
?>
4

1 回答 1

0

我能够通过添加 $stmt->bindValue 为非空字段添加以下内容来解决此问题：

foreach ($searchTerms as $field => $value) {
    if ($value != null && $value != '' && $value != ' ' ) {
        // Based on the key name in the array, decide which SQL statement to add to the array to be constructed
        switch ($field) {
            case 'locnum':
                            $stmt->bindValue(':locnum', $locnum, PDO::PARAM_INT);
                            break;
            case 'drawnum':
                            $stmt->bindValue(':drawnum', $drawnum, PDO::PARAM_INT);
                            break;
            case 'drawdate':
                            $stmt->bindValue(':drawdate', $drawdate, PDO::PARAM_STR);
                            break;         
        }              
    }             
}
于 2013-06-27T14:39:44.603 回答