40

我有一本字典：

import math
import random

d = {1: ["Spices", math.floor(random.gauss(40, 5))],
    2: ["Other stuff", math.floor(random.gauss(20, 5))],
    3: ["Tea", math.floor(random.gauss(50, 5))],
    10: ["Contraband", math.floor(random.gauss(1000, 5))],
    5: ["Fruit", math.floor(random.gauss(10, 5))],
    6: ["Textiles", math.floor(random.gauss(40, 5))]
}

我想把它打印出来，让它与标题很好地对齐。我可以将标题添加到字典中并始终确保它们排在首位吗？我已经看到了几种垂直执行此操作的方法，但我希望它的最大列宽接近最大 str() 或 int()。

例子：

键_________标签______________编号1____________香料_______________42
2____________其他东西_____________16 等

显然，我什至无法在此编辑器中手动执行此操作，但我希望这个想法能够实现。我也不是真的想要__。只是一个占位符。
谢谢大家。

4

6 回答 6

78

您可以在 python2 中使用字符串格式：

    print "{:<8} {:<15} {:<10}".format('Key','Label','Number')
    for k, v in d.iteritems():
        label, num = v
        print "{:<8} {:<15} {:<10}".format(k, label, num)

或者，python3 中的字符串格式：

    print("{:<8} {:<15} {:<10}".format('Key','Label','Number'))
    for k, v in d.items():
        label, num = v
        print("{:<8} {:<15} {:<10}".format(k, label, num))

输出：

Key      Label           Number    
1        Spices          38.0      
2        Other stuff     24.0      
3        Tea             44.0      
5        Fruit           5.0       
6        Textiles        37.0      
10       Contraband      1000.0
于 2013-06-26T20:53:46.220 回答
37

我正在寻找一种列宽未知的解决方案来打印数据库表。所以这里是：

def printTable(myDict, colList=None):
   """ Pretty print a list of dictionaries (myDict) as a dynamically sized table.
   If column names (colList) aren't specified, they will show in random order.
   Author: Thierry Husson - Use it as you want but don't blame me.
   """
   if not colList: colList = list(myDict[0].keys() if myDict else [])
   myList = [colList] # 1st row = header
   for item in myDict: myList.append([str(item[col] if item[col] is not None else '') for col in colList])
   colSize = [max(map(len,col)) for col in zip(*myList)]
   formatStr = ' | '.join(["{{:<{}}}".format(i) for i in colSize])
   myList.insert(1, ['-' * i for i in colSize]) # Seperating line
   for item in myList: print(formatStr.format(*item))

样本：

printTable([{'a':123,'bigtitle':456,'c':789},{'a':'x','bigtitle':'y','c':'z'}, \
    {'a':'2016-11-02','bigtitle':1.2,'c':78912313213123}], ['a','bigtitle','c'])

输出：

a          | bigtitle | c             
---------- | -------- | --------------
123        | 456      | 789           
x          | y        | z             
2016-11-02 | 1.2      | 78912313213123

在 Psycopg 上下文中，您可以这样使用它：

curPG.execute("SELECT field1, field2, ... fieldx FROM mytable")
printTable(curPG.fetchall(), [c.name for c in curPG.description])

如果您需要多行行的变体，这里是：

def printTable(myDict, colList=None, sep='\uFFFA'):
   """ Pretty print a list of dictionaries (myDict) as a dynamically sized table.
   If column names (colList) aren't specified, they will show in random order.
   sep: row separator. Ex: sep='\n' on Linux. Default: dummy to not split line.
   Author: Thierry Husson - Use it as you want but don't blame me.
   """
   if not colList: colList = list(myDict[0].keys() if myDict else [])
   myList = [colList] # 1st row = header
   for item in myDict: myList.append([str(item[col] or '') for col in colList])
   colSize = [max(map(len,(sep.join(col)).split(sep))) for col in zip(*myList)]
   formatStr = ' | '.join(["{{:<{}}}".format(i) for i in colSize])
   line = formatStr.replace(' | ','-+-').format(*['-' * i for i in colSize])
   item=myList.pop(0); lineDone=False
   while myList or any(item):
      if all(not i for i in item):
         item=myList.pop(0)
         if line and (sep!='\uFFFA' or not lineDone): print(line); lineDone=True
      row = [i.split(sep,1) for i in item]
      print(formatStr.format(*[i[0] for i in row]))
      item = [i[1] if len(i)>1 else '' for i in row]

样本：

sampleDict = [{'multi lines title': 12, 'bigtitle': 456, 'third column': '7 8 9'},
{'multi lines title': 'w x y z', 'bigtitle': 'b1 b2', 'third column': 'z y x'},
{'multi lines title': '2', 'bigtitle': 1.2, 'third column': 78912313213123}]

printTable(sampleDict, sep=' ')

输出：

bigtitle | multi | third         
         | lines | column        
         | title |               
---------+-------+---------------
456      | 12    | 7             
         |       | 8             
         |       | 9             
---------+-------+---------------
b1       | w     | z             
b2       | x     | y             
         | y     | x             
         | z     |               
---------+-------+---------------
1.2      | 2     | 78912313213123

没有sep参数，printTable(sampleDict)给你：

bigtitle | multi lines title | third column  
---------+-------------------+---------------
456      | 12                | 7 8 9         
b1 b2    | w x y z           | z y x         
1.2      | 2                 | 78912313213123
于 2016-11-02T20:40:42.860 回答
12

我更喜欢熊猫数据框

import pandas as pd
data = {'Name': ['a', 'b', 'c'], 'Age': [10, 11, 12]}
df = pd.DataFrame(data)
print(df)

输出： 

  Name  Age
0    a   10
1    b   11
2    c   12

在此处查看有关打印漂亮数据框的更多信息

于 2019-08-14T05:33:23.603 回答
3

字符串格式化提供了一个很好、简单的解决方案。这个答案是来自@Ashwini 的好答案的 Python 3 的更新。

str_fmt = "{:<8} {:<15} {:<10}"
print(str_fmt.format('Key','Label','Number'))
for k, v in d.items():
    label, num = v
    print(str_fmt.format(k, label, num))
于 2020-10-23T15:07:54.083 回答
2

基于 Le Droid 的代码，我为每一行添加了分隔符“-”，这可以使打印更清晰。谢谢，Le Droid。

def printTable(myDict, colList=None):
    if not colList: 
        colList = list(myDict[0].keys() if myDict else [])
    myList = [colList] # 1st row = header
    for item in myDict: 
        myList.append([str(item[col] or '') for col in colList])
    #maximun size of the col for each element
    colSize = [max(map(len,col)) for col in zip(*myList)]
    #insert seperating line before every line, and extra one for ending. 
    for i in  range(0, len(myList)+1)[::-1]:
         myList.insert(i, ['-' * i for i in colSize])
    #two format for each content line and each seperating line
    formatStr = ' | '.join(["{{:<{}}}".format(i) for i in colSize])
    formatSep = '-+-'.join(["{{:<{}}}".format(i) for i in colSize])
    for item in myList: 
        if item[0][0] == '-':
            print(formatSep.format(*item))
        else:
            print(formatStr.format(*item))

输出：

-----------+----------+---------------
a          | bigtitle | c             
-----------+----------+---------------
123        | 456      | 789           
-----------+----------+---------------
x          | y        | z             
-----------+----------+---------------
2016-11-02 | 1.2      | 78912313213123
-----------+----------+---------------
于 2018-08-10T12:36:32.603 回答
-1

您可以使用 ljust 或 rjust 字符串方法：

print key.ljust(10), label.ljust(30), number.ljust(20)
于 2013-06-26T21:20:28.060 回答