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假设我创建了一个带有两列b（一个 DateTime）和c一个（一个整数）的 pandas DataFrame。现在我想从第一列 ( b) 中的值创建一个 DatetimeIndex：

import pandas as pd
import datetime as dt

a=[1371215423523845, 1371215500149460, 1371215500273673, 1371215500296504, 1371215515568529, 1371215531603530, 1371215576463339, 1371215579939113, 1371215731215054, 1371215756231343, 1371215756417484, 1371215756519690, 1371215756551645, 1371215756578979, 1371215770164647, 1371215820891387, 1371215821305584, 1371215824925723, 1371215878061146, 1371215878173401, 1371215890324572, 1371215898024253, 1371215926634930, 1371215933513122, 1371216018210826, 1371216080844727, 1371216080930036, 1371216098471787, 1371216111858392, 1371216326271516, 1371216326357836, 1371216445401635, 1371216445401635, 1371216481057049, 1371216496791894, 1371216514691786, 1371216540337354, 1371216592180666, 1371216592339578, 1371216605823474, 1371216610332627, 1371216623042903, 1371216624749566, 1371216630631179, 1371216654267672, 1371216714011662, 1371216783761738, 1371216783858402, 1371216783858402, 1371216783899118, 1371216976339169, 1371216976589850, 1371217028278777, 1371217028560770, 1371217170996479, 1371217176184425, 1371217176318245, 1371217190349372, 1371217190394753, 1371217272797618, 1371217340235667, 1371217340358197, 1371217340433146, 1371217340463797, 1371217340490876, 1371217363797722, 1371217363797722, 1371217363890678, 1371217363922929, 1371217523548405, 1371217523548405, 1371217551181926, 1371217551181926, 1371217551262975, 1371217652579855, 1371218091071955, 1371218295006690, 1371218370005139, 1371218370133637, 1371218370133637, 1371218370158096, 1371218370262823, 1371218414896836, 1371218415013417, 1371218415050485, 1371218415050485, 1371218504396524, 1371218504396524, 1371218504481537, 1371218504517462, 1371218586980079, 1371218719953887, 1371218720621245, 1371218738776732, 1371218937926310, 1371218954785466, 1371218985347070, 1371218985421615, 1371219039790991, 1371219171650043]
b=[dt.datetime.fromtimestamp(t/1000000.) for t in a]
c = {'b':b, 'c':a[:]}


df = pd.DataFrame(c)
df.set_index(pd.DatetimeIndex(df['b']))
print df

一切似乎都很好，除了当我打印 DataFrame 时，它​​说它有一个 Int64Index。

<class 'pandas.core.frame.DataFrame'>
Int64Index: 100 entries, 0 to 99
Data columns (total 2 columns):
b    100  non-null values
c    100  non-null values
dtypes: datetime64[ns](1), int64(1)

我做错了什么还是我没有正确理解 Indeces 的概念？

4

1 回答 1

61

set_index不是就地（除非你通过inplace=True）。否则都是正确的

In [7]: df = df.set_index(pd.DatetimeIndex(df['b']))

In [8]: df
Out[8]: 
<class 'pandas.core.frame.DataFrame'>
DatetimeIndex: 100 entries, 2013-06-14 09:10:23.523845 to 2013-06-14 10:12:51.650043
Data columns (total 2 columns):
b    100  non-null values
c    100  non-null values
dtypes: datetime64[ns](1), int64(1)

同样作为仅供参考，在即将发布的 0.12 版本（下周）中，您可以通过unit=us指定自纪元以来的微秒单位

In [13]: pd.to_datetime(a,unit='us')
Out[13]: 
<class 'pandas.tseries.index.DatetimeIndex'>
[2013-06-14 13:10:23.523845, ..., 2013-06-14 14:12:51.650043]
Length: 100, Freq: None, Timezone: None
于 2013-06-26T19:31:58.437 回答