2

I'm trying to use jquery and PHP to upload an image like so:

HTML

<form id="form-photo" enctype="multipart/form-data"><
  <span class="btn btn-small fileinput-button">
    <span>Add Photo</span>
    <input type="file" name="photo-img" id="photo-img">
  </span>
</form>

Current jquery framework looks like this:

$('#photo-img').change(function(){
    var file = this.files[0];

    //console.log(file);
    name = file.name;
    size = file.size;
    type = file.type;

    // I'll do some validation here before proceeding

    var formData = new FormData($('#form-photo'));

    console.log(formData);

   // How do I pass the image form data to a PHP function via jquery?

});

Can I just pass the formData to a PHP function via jquery post?

4

3 回答 3

5

测试并在Goolge Chrome, Opera, Firefox,上工作Safari。
doesn't work with IE8 or lower

Javascript

创建一个对象并在索引的帮助下FormData将其附加到您的服务器filephoto-imgPOSTXMLHttpRequest

$(function() {
  $('#photo-img').change(function(){
    var file  = this.files[0];

    // do your validation here

    var formData  = new FormData();
    formData.append( 'photo-img', file ); // append the file to form data

    var xhr = false;
    if ( typeof XMLHttpRequest !== 'undefined' ) {
      xhr = new XMLHttpRequest();
    }
    else {
      var versions  = [ "MSXML2.XmlHttp.5.0", "MSXML2.XmlHttp.4.0", "MSXML2.XmlHttp.3.0", "MSXML2.XmlHttp.2.0", "Microsoft.XmlHttp" ];
      for( var i = 0, len = versions.length; i < len; i++ ) {
        try {
          xhr = new ActiveXObject( versions[i] );
          break;
        }
        catch(e) {}
      }
    }
    if ( xhr ) {
      // replace test.php with your own upload script url
      xhr.open( "POST", "test.php", true );
      xhr.onreadystatechange  = function() {
        if ( this.readyState === 4 && this.status == 200 ) {
          var response  = this.response || this.responseText;

          /** Do Something with the reponse **/
          response  = $.parseJSON( response );
          if ( response && response.message ) {
            window.alert( response.message );
          }

        }
      }
      // now send the formData to server
      xhr.send( formData );
    }
  });
});

PHP

服务器端更好的图像上传处理并返回一个JSON对象作为响应

<?php
  if ( isset( $_FILES["photo-img"] ) ) {
    $error  = false;
    $image  = $_FILES["photo-img"];
    $code   = (int)$image["error"];
    $valid  = array( IMAGETYPE_PNG, IMAGETYPE_JPEG, IMAGETYPE_GIF );
    $folder = dirname( __FILE__ )."/upload/"; // path to folder to where you want to move uploaded file
    $target = $folder.$image["name"];

    if ( !file_exists( $folder ) ) {
      @mkdir( $folder, 0755, true ) ;
    }

    if ( $code !== UPLOAD_ERR_OK ) {
      switch( $code ) {
        case UPLOAD_ERR_INI_SIZE:
          $error  = 'Error '.$code.': The uploaded file exceeds the <a href="http://www.php.net/manual/en/ini.core.php#ini.upload-max-filesize" target="_blank" rel="nofollow"><span class="function-string">upload_max_filesize</span></a> directive in php.ini';
        break;
        case UPLOAD_ERR_FORM_SIZE:
          $error  = 'Error '.$code.': The uploaded file exceeds the <span class="const-string">MAX_FILE_SIZE</span> directive that was specified in the HTML form';
        break;
        case UPLOAD_ERR_PARTIAL:
          $error  = 'Error '.$code.': The uploaded file was only partially uploaded';
        break;
        case UPLOAD_ERR_NO_FILE:
          $error  = 'Error '.$code.': No file was uploaded';
        break;
        case UPLOAD_ERR_NO_TMP_DIR:
          $error  = 'Error '.$code.': Missing a temporary folder';
        break;
        case UPLOAD_ERR_CANT_WRITE:
          $error  = 'Error '.$code.': Failed to write file to disk';
        break;
        case UPLOAD_ERR_EXTENSION:
          $error  = 'Error '.$code.': A PHP extension stopped the file upload';
        break;
        default:
          $error  = 'Error '.$code.': Unknown upload error'; 
        break; 
      }
    }
    else {
      $iminfo = @getimagesize( $image["tmp_name"] );
      if ( $iminfo && is_array( $iminfo ) ) {
        if ( isset( $iminfo[2] ) && in_array( $iminfo[2], $valid ) && is_readable( $image["tmp_name"] ) ) {
          if ( !move_uploaded_file( $image["tmp_name"], $target ) ) {
            $error  = "Error while moving uploaded file";
          }
        }
        else {
          $error  = "Invalid format or image is not readable";
        }
      }
      else {
        $error  = "Only image files are allowed (jpg, gif, png)";
      }
    }
    if ( empty( $error ) ) {
      echo json_encode( array( "error" => 0, "message" => "Upload success!" ) );
    }
    else {
      echo json_encode( array( "error" => 1, "message" => $error ) );
    }
    exit();
  }
?>
于 2013-06-26T18:47:48.183 回答
2

请注意，$.post 和 $.ajax 非常相似（除了默认情况下 $.ajax 使用 type=get，您必须将其更改为 type=post）。使用 $.ajax 可以更好地控制内容，但 $.post 更加流畅——将 $.post 视为执行 AJAX POST 的一种简写方式。但是，由于 $.ajax 通常比 $.post 更有条理，因此对于 AJAX 新手来说，这是一个尝试添加修饰符的好方法，例如dataType:JSON, contentType，甚至 async:false。

Ajax 代码是这样的：

$('#photo-img').change(function(){
    var file = this.files[0];

    //console.log(file);
    name = file.name;
    size = file.size;
    type = file.type;

    $.ajax({
        type: "POST",
        url: "your_php_file.php",
        data: 'f_name=' +name+ '&f_size=' +size+ '&f_type=' +type,
        success: function(whatigot) {
            alert('Server-side response: ' + whatigot);
        } //END success fn
    }); //END $.ajax
}); //END dropdown change event

请注意，从 PHP 文件返回的任何数据都会在 AJAX 调用的成功函数中进入您的 HTML 文档，并且必须在那里进行处理。这就是您将接收到的数据插入 DOM 的地方。

例如，假设您的 HTML 文档有一个带有id="myDiv". 要将 PHP 中的数据插入 HTML 文档，请将行：替换为alert('Server-side response: ' + whatigot);：

$('#myDiv').html(whatIgot);

您的 DIV 现在包含从 PHP 文件回显的数据。

在 PHP 方面，它基本上看起来像这样：

<?php
    $file_name = $_POST['f_name'];
    $file_size = $_POST['f_size'];
    $file_type = $_POST['f_type'];

    //Here is where you do some stuff, such as MySQL lookups, etc
    //Then build the response to send back (default is HTML, unless 
    //you specify something else like JSON)

    $r = 'The PHP File received:<br><br>';
    $r .= '
        <ul>
            <li>File Name: ' .$file_name.'</li>
            <li>File Size: ' .$file_size.'</li>
            <li>File Type: ' .$file_type.'</li>
        </ul>
    ';
    echo $r;

有关其工作原理的想法，请参阅此示例。

请注意，上面的示例使用 jQuery，因此需要在页面的标签中引用此引用：

<head>
    <script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
</head>
于 2013-06-26T18:41:26.220 回答
2

您可以在 jquery 中使用 $.ajax 方法并将表单数据发送到 php 文件。 

 $.ajax({
  type: "POST",
  url: "http://localhost/index.php",
  data: data,
  success: success,
});
于 2013-06-26T18:22:57.497 回答