2

我在面向 Web 开发人员的 Eclipse Java EE IDE 中有一个 Maven 项目（带有 Web 和 JPA 方面）。我已将 jars 添加到我的 tomcat 库中，并且一切都编译得很好。

但是，我的网页标题并未反映我通过CORS 过滤器在 web.xml 中启用的内容。

我的标题看起来像：

在此处输入图像描述

我的 web.xml 包含：

<?xml version="1.0" encoding="utf-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">

<!-- Servlet 1: Expose the OData service endpoint -->
<servlet>
<servlet-name>OData</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>

<!-- all additional parameters will be passed to your factory create method -->
<init-param>
  <param-name>javax.ws.rs.Application</param-name>
  <param-value>org.odata4j.jersey.producer.resources.ODataApplication</param-value>
</init-param>

<init-param>
    <param-name>odata4j.producerfactory</param-name>
    <param-value>org.odata4j.producer.jpa.JPAProducerFactory</param-value>
</init-param>

<init-param>
  <param-name>odata4j.jpa.persistenceUnitName</param-name>
  <param-value>Resource</param-value>
</init-param>

<load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
<servlet-name>OData</servlet-name>
<url-pattern>/example.svc/*</url-pattern>
</servlet-mapping>

<!-- Servlet 2: Enable crossdomain access for browser clients -->
<servlet>
<servlet-name>CrossDomain</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
  <param-name>javax.ws.rs.Application</param-name>
  <param-value>org.odata4j.producer.resources.RootApplication</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>CrossDomain</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>


<!--  Use CORSFilter for CORS -->
<filter>
<filter-name>CORS</filter-name>
<filter-class>com.thetransactioncompany.cors.CORSFilter</filter-class>
<!-- Note: All parameters are options, if ommitted CORS Filter
   will fall back to the respective default values.
-->
<init-param>
<param-name>cors.allowGenericHttpRequests</param-name>
<param-value>true</param-value>
</init-param>

<init-param>
<param-name>cors.allowOrigin</param-name>
<param-value>*</param-value>
</init-param>

<init-param>
<param-name>cors.supportedMethods</param-name>
<param-value>GET, HEAD, POST, OPTIONS, PUT, DELETE</param-value>
</init-param>

<init-param>
<param-name>cors.supportedHeaders</param-name>
<param-value>Content-Type, X-Requested-With, Accept, Authentication</param-value>
</init-param>

<init-param>
<param-name>cors.exposedHeaders</param-name>
<param-value>X-Test-1, X-Test-2</param-value>
</init-param>

<init-param>
<param-name>cors.supportsCredentials</param-name>
<param-value>true</param-value>
</init-param>

<init-param>
<param-name>cors.maxAge</param-name>
<param-value>3600</param-value>
</init-param>

</filter>

<filter-mapping>
<filter-name>CORS</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>

</web-app>
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1 回答 1

3

我通过为 Java 应用程序实现 Padcom 的 CORS 过滤器来修复我的标头以支持 CORS，如此处所述。

我仍然不确定为什么我上面尝试的方法不起作用......但是如果你坚持尝试上面的方法，那么尝试 Padcom 的方法很容易并且可以工作。:)

于 2013-06-28T13:33:12.967 回答