javascript - Google Maps API v3 格式纬度经度

Question

在 Google 地图中，event.latlng.lat() 将地理纬度/经度表示为十进制数。我需要将数字 53.5030167、8.0528333 格式化为字符串 N 53°30.181' E 008°03.170'。不幸的是，下面的代码不起作用。我的错误在哪里？

<script>
   var map;

    function initialize() {
        map = new google.maps.Map(document.getElementById('map_canvas'), {
            center: new google.maps.LatLng(54, 8),
            zoom: 14,
            maxZoom: 21,
            mapTypeId: google.maps.MapTypeId.TERRAIN,
            panControl: false,
            draggableCursor: "default",
            streetViewControl: false
        });

        google.maps.event.addListener(map,'click',function(event) {
            document.getElementById('latlngclick').value = dec2StrLat(event.latLng.lat()) + ', ' + dec2StrLng(event.latLng.lng())
        })

        google.maps.event.addListener(map,'mousemove',function(event) {
            document.getElementById('latspan').innerHTML = dec2StrLat(event.latLng.lat())
            document.getElementById('lngspan').innerHTML = dec2StrLng(event.latLng.lng())
        });

    google.maps.event.addDomListener(window, 'load', initialize);

    function dec2StrLat(decLatitude) {
        var intDegree;
        var decMinute;
        var strLatitude = "N";
        if (decLatitude < 0) {
            strLatitude = "S";
            decLatitude = decLatitude * -1;
        }
        intDegree = Math.floor(decLatitude);
        decMinute = (decLatitude - intDegree) * 60;
        decMinute = myRound(decMinute, 3);
        strLatitude = strLatitude + " " + String(intDegree) +"° " + String(decMinute) +"'";
        return strLatitude
    }

    function dec2StrLng(decLongitude) {
        var intDegree
        var decMinute
        strLongitude = "E";
        if (decLongitude < 0) {
            strLongitude = "W";
            decLongitude = decLongitude * -1;
        }
        intDegree = Math.floor(decLongitude);
        decMinute = (decLongitude - intDegree) * 60;
        decMinute = myRound(decMinute, 3)
        strLongitude = strLongitude + " " + String(intDegree) +"° " + String(decMinute) +"'";
        return strLongitude
    }


</script>