我有一个包含日期yyyy/mm/dd格式的字符串变量。如何将其转换为time_tC++ 中的类型？例如：string date_details = "2012/09/12"
另外，如何比较两个包含日期的变量来决定哪个是 C++ 中最早的？例如：string curr_date = "2012/09/13" string user_date = "2012/09/12"
谢谢。
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14433 次
5 回答
10
以年-月-日格式比较两个日期strcmp就足够了：
assert(strcmp("2012/09/13", "2012/09/12") > 0);
assert(strcmp("2012/10/13", "2013/01/12") < 0);
于 2013-06-26T12:14:13.570 回答
1
自您的示例日期以来，它的价值string curr_date = "2012/09/13"似乎string curr_date = "2012/09/13"是 ISO8601格式（除了使用“/”作为分隔符）。ISO8601 的乐趣在于字典顺序与时间顺序相同......即对字符串进行排序，您也可以按时间排序。
这很吸引人，因为它提供了一种处理许多日期的好方法（而不是只有 2 个）
#include <algorithm>
#include <vector>
#include <string>
using namespace std;
int main()
{
vector<string> v = getDates(); //Made up function returning a vector of ISO dates
sort(v, v.begin(), v.end()); //Done
//Do whatever you have to
return 0;
}
于 2013-06-26T12:15:42.827 回答
1
如果需要，您可以使用strptime任何格式解析日期，然后mktime将tm结构转换为time_t可以比较的值。
于 2013-06-26T12:12:25.677 回答
0
strptime()就是你要找的。不幸的是，让它在 Windows 上工作并不容易。
尽管经过多次谷歌搜索，我终于在ffmpeg.org上找到了一个可以完成这项工作的实现。该实现可在plibc.sourceforge.net（适用于 Windows 的 POSIX 兼容的 libc）上 找到。
如果要使用此 regex 从 doxygen 复制行号，则必须删除行号00([0-9])([0-9])([0-9])。还有一个错误@第 115 行enum locale_status { not, loc, raw };必须更改为enum locale_status { nott, loc, raw };.
或者，如果您对我使用的所有版本都太懒了：
/* Convert a string representation of time to a time value.
Copyright (C) 1996, 1997, 1998, 1999, 2000 Free Software Foundation, Inc.
This file is part of the GNU C Library.
Contributed by Ulrich Drepper <drepper@cygnus.com>, 1996.
The GNU C Library is free software; you can redistribute it and/or
modify it under the terms of the GNU Library General Public License as
published by the Free Software Foundation; either version 2 of the
License, or (at your option) any later version.
The GNU C Library is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
Library General Public License for more details.
You should have received a copy of the GNU Library General Public
License along with the GNU C Library; see the file COPYING.LIB. If not,
write to the Free Software Foundation, Inc., 59 Temple Place - Suite 330,
Boston, MA 02111-1307, USA. */
void get_locale_strings(void);
/* XXX This version of the implementation is not really complete.
Some of the fields cannot add information alone. But if seeing
some of them in the same format (such as year, week and weekday)
this is enough information for determining the date. */
#include <ctype.h>
#include <limits.h>
#include <string.h>
#include <time.h>
#define match_char(ch1, ch2) if (ch1 != ch2) return NULL
#ifndef Macintosh
#if defined __GNUC__ && __GNUC__ >= 2
# define match_string(cs1, s2) \
({ size_t len = strlen (cs1); \
int result = strncasecmp ((cs1), (s2), len) == 0; \
if (result) (s2) += len; \
result; })
#else
/* Oh come on. Get a reasonable compiler. */
# define match_string(cs1, s2) \
(strncasecmp ((cs1), (s2), strlen (cs1)) ? 0 : ((s2) += strlen (cs1), 1))
#endif
#else
# define match_string(cs1, s2) \
(strncmp ((cs1), (s2), strlen (cs1)) ? 0 : ((s2) += strlen (cs1), 1))
#endif /* mac */
/* We intentionally do not use isdigit() for testing because this will
lead to problems with the wide character version. */
#define get_number(from, to, n) \
do { \
int __n = n; \
val = 0; \
while (*rp == ' ') \
++rp; \
if (*rp < '0' || *rp > '9') \
return NULL; \
do { \
val *= 10; \
val += *rp++ - '0'; \
} while (--__n > 0 && val * 10 <= to && *rp >= '0' && *rp <= '9'); \
if (val < from || val > to) \
return NULL; \
} while (0)
# define get_alt_number(from, to, n) \
/* We don't have the alternate representation. */ \
get_number(from, to, n)
#define recursive(new_fmt) \
(*(new_fmt) != '\0' \
&& (rp = strptime_internal (rp, (new_fmt), tm, decided)) != NULL)
/* This version: may overwrite these with versions for the locale */
static char weekday_name[][20] =
{
"Sunday", "Monday", "Tuesday", "Wednesday",
"Thursday", "Friday", "Saturday"
};
static char ab_weekday_name[][10] =
{
"Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat"
};
static char month_name[][20] =
{
"January", "February", "March", "April", "May", "June",
"July", "August", "September", "October", "November", "December"
};
static char ab_month_name[][10] =
{
"Jan", "Feb", "Mar", "Apr", "May", "Jun",
"Jul", "Aug", "Sep", "Oct", "Nov", "Dec"
};
static char am_pm[][4] = {"AM", "PM"};
# define HERE_D_T_FMT "%a %b %e %H:%M:%S %Y"
# define HERE_D_FMT "%y/%m/%d"
# define HERE_T_FMT_AMPM "%I:%M:%S %p"
# define HERE_T_FMT "%H:%M:%S"
static const unsigned short int __mon_yday[2][13] =
{
/* Normal years. */
{ 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365 },
/* Leap years. */
{ 0, 31, 60, 91, 121, 152, 182, 213, 244, 274, 305, 335, 366 }
};
/* Status of lookup: do we use the locale data or the raw data? */
enum locale_status { nott, loc, raw };
# define __isleap(year) \
((year) % 4 == 0 && ((year) % 100 != 0 || (year) % 400 == 0))
/* Compute the day of the week. */
void
day_of_the_week (struct tm *tm)
{
/* We know that January 1st 1970 was a Thursday (= 4). Compute the
the difference between this data in the one on TM and so determine
the weekday. */
int corr_year = 1900 + tm->tm_year - (tm->tm_mon < 2);
int wday = (-473
+ (365 * (tm->tm_year - 70))
+ (corr_year / 4)
- ((corr_year / 4) / 25) + ((corr_year / 4) % 25 < 0)
+ (((corr_year / 4) / 25) / 4)
+ __mon_yday[0][tm->tm_mon]
+ tm->tm_mday - 1);
tm->tm_wday = ((wday % 7) + 7) % 7;
}
/* Compute the day of the year. */
void
day_of_the_year (struct tm *tm)
{
tm->tm_yday = (__mon_yday[__isleap (1900 + tm->tm_year)][tm->tm_mon]
+ (tm->tm_mday - 1));
}
char *
strptime_internal (const char *rp, const char *fmt, struct tm *tm,
enum locale_status *decided)
{
const char *rp_backup;
int cnt;
size_t val;
int have_I, is_pm;
int century, want_century;
int have_wday, want_xday;
int have_yday;
int have_mon, have_mday;
have_I = is_pm = 0;
century = -1;
want_century = 0;
have_wday = want_xday = have_yday = have_mon = have_mday = 0;
while (*fmt != '\0')
{
/* A white space in the format string matches 0 more or white
space in the input string. */
if (isspace (*fmt))
{
while (isspace (*rp))
++rp;
++fmt;
continue;
}
/* Any character but `%' must be matched by the same character
in the iput string. */
if (*fmt != '%')
{
match_char (*fmt++, *rp++);
continue;
}
++fmt;
/* We need this for handling the `E' modifier. */
start_over:
/* Make back up of current processing pointer. */
rp_backup = rp;
switch (*fmt++)
{
case '%':
/* Match the `%' character itself. */
match_char ('%', *rp++);
break;
case 'a':
case 'A':
/* Match day of week. */
for (cnt = 0; cnt < 7; ++cnt)
{
if (*decided != loc
&& (match_string (weekday_name[cnt], rp)
|| match_string (ab_weekday_name[cnt], rp)))
{
*decided = raw;
break;
}
}
if (cnt == 7)
/* Does not match a weekday name. */
return NULL;
tm->tm_wday = cnt;
have_wday = 1;
break;
case 'b':
case 'B':
case 'h':
/* Match month name. */
for (cnt = 0; cnt < 12; ++cnt)
{
if (match_string (month_name[cnt], rp)
|| match_string (ab_month_name[cnt], rp))
{
*decided = raw;
break;
}
}
if (cnt == 12)
/* Does not match a month name. */
return NULL;
tm->tm_mon = cnt;
want_xday = 1;
break;
case 'c':
/* Match locale's date and time format. */
if (!recursive (HERE_T_FMT_AMPM))
return NULL;
break;
case 'C':
/* Match century number. */
get_number (0, 99, 2);
century = val;
want_xday = 1;
break;
case 'd':
case 'e':
/* Match day of month. */
get_number (1, 31, 2);
tm->tm_mday = val;
have_mday = 1;
want_xday = 1;
break;
case 'F':
if (!recursive ("%Y-%m-%d"))
return NULL;
want_xday = 1;
break;
case 'x':
/* Fall through. */
case 'D':
/* Match standard day format. */
if (!recursive (HERE_D_FMT))
return NULL;
want_xday = 1;
break;
case 'k':
case 'H':
/* Match hour in 24-hour clock. */
get_number (0, 23, 2);
tm->tm_hour = val;
have_I = 0;
break;
case 'I':
/* Match hour in 12-hour clock. */
get_number (1, 12, 2);
tm->tm_hour = val % 12;
have_I = 1;
break;
case 'j':
/* Match day number of year. */
get_number (1, 366, 3);
tm->tm_yday = val - 1;
have_yday = 1;
break;
case 'm':
/* Match number of month. */
get_number (1, 12, 2);
tm->tm_mon = val - 1;
have_mon = 1;
want_xday = 1;
break;
case 'M':
/* Match minute. */
get_number (0, 59, 2);
tm->tm_min = val;
break;
case 'n':
case 't':
/* Match any white space. */
while (isspace (*rp))
++rp;
break;
case 'p':
/* Match locale's equivalent of AM/PM. */
if (!match_string (am_pm[0], rp))
if (match_string (am_pm[1], rp))
is_pm = 1;
else
return NULL;
break;
case 'r':
if (!recursive (HERE_T_FMT_AMPM))
return NULL;
break;
case 'R':
if (!recursive ("%H:%M"))
return NULL;
break;
case 's':
{
/* The number of seconds may be very high so we cannot use
the `get_number' macro. Instead read the number
character for character and construct the result while
doing this. */
time_t secs = 0;
if (*rp < '0' || *rp > '9')
/* We need at least one digit. */
return NULL;
do
{
secs *= 10;
secs += *rp++ - '0';
}
while (*rp >= '0' && *rp <= '9');
if ((tm = localtime (&secs)) == NULL)
/* Error in function. */
return NULL;
}
break;
case 'S':
get_number (0, 61, 2);
tm->tm_sec = val;
break;
case 'X':
/* Fall through. */
case 'T':
if (!recursive (HERE_T_FMT))
return NULL;
break;
case 'u':
get_number (1, 7, 1);
tm->tm_wday = val % 7;
have_wday = 1;
break;
case 'g':
get_number (0, 99, 2);
/* XXX This cannot determine any field in TM. */
break;
case 'G':
if (*rp < '0' || *rp > '9')
return NULL;
/* XXX Ignore the number since we would need some more
information to compute a real date. */
do
++rp;
while (*rp >= '0' && *rp <= '9');
break;
case 'U':
case 'V':
case 'W':
get_number (0, 53, 2);
/* XXX This cannot determine any field in TM without some
information. */
break;
case 'w':
/* Match number of weekday. */
get_number (0, 6, 1);
tm->tm_wday = val;
have_wday = 1;
break;
case 'y':
/* Match year within century. */
get_number (0, 99, 2);
/* The "Year 2000: The Millennium Rollover" paper suggests that
values in the range 69-99 refer to the twentieth century. */
tm->tm_year = val >= 69 ? val : val + 100;
/* Indicate that we want to use the century, if specified. */
want_century = 1;
want_xday = 1;
break;
case 'Y':
/* Match year including century number. */
get_number (0, 9999, 4);
tm->tm_year = val - 1900;
want_century = 0;
want_xday = 1;
break;
case 'Z':
/* XXX How to handle this? */
break;
case 'E':
/* We have no information about the era format. Just use
the normal format. */
if (*fmt != 'c' && *fmt != 'C' && *fmt != 'y' && *fmt != 'Y'
&& *fmt != 'x' && *fmt != 'X')
/* This is an invalid format. */
return NULL;
goto start_over;
case 'O':
switch (*fmt++)
{
case 'd':
case 'e':
/* Match day of month using alternate numeric symbols. */
get_alt_number (1, 31, 2);
tm->tm_mday = val;
have_mday = 1;
want_xday = 1;
break;
case 'H':
/* Match hour in 24-hour clock using alternate numeric
symbols. */
get_alt_number (0, 23, 2);
tm->tm_hour = val;
have_I = 0;
break;
case 'I':
/* Match hour in 12-hour clock using alternate numeric
symbols. */
get_alt_number (1, 12, 2);
tm->tm_hour = val - 1;
have_I = 1;
break;
case 'm':
/* Match month using alternate numeric symbols. */
get_alt_number (1, 12, 2);
tm->tm_mon = val - 1;
have_mon = 1;
want_xday = 1;
break;
case 'M':
/* Match minutes using alternate numeric symbols. */
get_alt_number (0, 59, 2);
tm->tm_min = val;
break;
case 'S':
/* Match seconds using alternate numeric symbols. */
get_alt_number (0, 61, 2);
tm->tm_sec = val;
break;
case 'U':
case 'V':
case 'W':
get_alt_number (0, 53, 2);
/* XXX This cannot determine any field in TM without
further information. */
break;
case 'w':
/* Match number of weekday using alternate numeric symbols. */
get_alt_number (0, 6, 1);
tm->tm_wday = val;
have_wday = 1;
break;
case 'y':
/* Match year within century using alternate numeric symbols. */
get_alt_number (0, 99, 2);
tm->tm_year = val >= 69 ? val : val + 100;
want_xday = 1;
break;
default:
return NULL;
}
break;
default:
return NULL;
}
}
if (have_I && is_pm)
tm->tm_hour += 12;
if (century != -1)
{
if (want_century)
tm->tm_year = tm->tm_year % 100 + (century - 19) * 100;
else
/* Only the century, but not the year. Strange, but so be it. */
tm->tm_year = (century - 19) * 100;
}
if (want_xday && !have_wday) {
if ( !(have_mon && have_mday) && have_yday) {
/* we don't have tm_mon and/or tm_mday, compute them */
int t_mon = 0;
while (__mon_yday[__isleap(1900 + tm->tm_year)][t_mon] <= tm->tm_yday)
t_mon++;
if (!have_mon)
tm->tm_mon = t_mon - 1;
if (!have_mday)
tm->tm_mday = tm->tm_yday - __mon_yday[__isleap(1900 + tm->tm_year)][t_mon - 1] + 1;
}
day_of_the_week (tm);
}
if (want_xday && !have_yday)
day_of_the_year (tm);
return (char *) rp;
}
char *
strptime (const char *buf, const char *format, struct tm *tm)
{
enum locale_status decided;
#ifdef HAVE_LOCALE_H
if(!have_used_strptime) {
get_locale_strings();
/* have_used_strptime = 1; might change locale during session */
}
#endif
decided = raw;
return strptime_internal (buf, format, tm, &decided);
}
#ifdef HAVE_LOCALE_H
void get_locale_strings(void)
{
int i;
struct tm tm;
char buff[4];
tm.tm_sec = tm.tm_min = tm.tm_hour = tm.tm_mday = tm.tm_mon
= tm.tm_isdst = 0;
tm.tm_year = 30;
for(i = 0; i < 12; i++) {
tm.tm_mon = i;
strftime(ab_month_name[i], 10, "%b", &tm);
strftime(month_name[i], 20, "%B", &tm);
}
tm.tm_mon = 0;
for(i = 0; i < 7; i++) {
tm.tm_mday = tm.tm_yday = i+1; /* 2000-1-2 was a Sunday */
tm.tm_wday = i;
strftime(ab_weekday_name[i], 10, "%a", &tm);
strftime(weekday_name[i], 20, "%A", &tm);
}
tm.tm_hour = 1;
/* in locales where these are unused, they may be empty: better
not to reset them then */
strftime(buff, 4, "%p", &tm);
if(strlen(buff)) strcpy(am_pm[0], buff);
tm.tm_hour = 13;
strftime(buff, 4, "%p", &tm);
if(strlen(buff)) strcpy(am_pm[1], buff);
}
#endif
这是一个工作示例：
#include <iostream>
#include <string>
#include <cstdlib>
#include <cstring>
#include <time.h>
#include <stdio.h>
#include "strptime.h"
using namespace std;
int main()
{
struct tm tm1, tm2;
time_t t1, t2;
memset(&tm1, 0, sizeof(struct tm));
memset(&tm2, 0, sizeof(struct tm));
strptime("12 February 2010", "%d %b %Y", &tm1);
strptime("11 February 2010", "%d %b %Y", &tm2);
t1 = mktime(&tm1);
t2 = mktime(&tm2);
cout << t1 << endl;
cout << t2 << endl;
if (t1 > t2)
{
cout << "t1 > t2" << endl;
}
else if (t1 == t2)
{
cout << "t1 == t2" << endl;
}
else if (t1 < t2)
{
cout << "t1 < t2" << endl;
}
cout << (t1 - t2) << endl;
return 0;
}
输出：
1265925600
1265839200
t1 > t2
86400
于 2013-06-26T13:19:12.320 回答
0
我的建议是使用仿函数。这样做可以让您准确地确定要如何比较这些日期，并让您以后能够定义另一个以不同方式比较日期的仿函数。
例如，您可以这样定义函子：
struct DateLessThan
{
BOOL operator()(const std::string& lhs, const std::string& rhs)
{
// the following is pseudocode
split lhs and rhs into arrays of strings based on the delimiter "/"
convert the string arrays into integers and store them in vars (possibly lhs_day, lhs_month, etc.)
if (lhs_year < rhs_year)
return true;
else if (lhs_year == rhs_year)
{
if (lhs_month < rhs_month)
return true;
else if (lhs_month == rhs_month)
{
if (lhs_day < rhs_day)
return true;
}
}
return false;
}
};
于 2013-06-26T13:10:54.650 回答