3

我有一个产生如下结果的表：

Code   Month    Value

733     May      520.00
733     May     2250.00
733     May      125.00

我有一个要求，我需要在上面显示这样的记录：

Code    May
733      520
733     2250
733      125

我可以通过选择枢轴来想到一种方法，所以我想：

Select 
    Code,
    IsNull(January,0)[January(Actual)],          
    IsNull(February,0)[February(Actual)],              
    IsNull(March,0)[March(Actual)],              
    IsNull(April,0)[April(Actual)],              
    IsNull(May,0)[May(Actual)],              
    IsNull(June,0)[June(Actual)],              
    IsNull(July,0)[July(Actual)],              
    IsNull(August,0)[August(Actual)],              
    IsNull(September,0)[September(Actual)],              
    IsNull(October,0)[October(Actual)],              
    IsNull(November,0)[November(Actual)],              
    IsNull(December,0)[December(Actual)]
From 
    (
    Select 
         Code,
         [Month],
         Value
    From 
        #tempMonthWiseActualValue
    )s 
Pivot  
    (
         min([Value] )
         For [Month]           
        In    (January,February,March,April,May,June,July,August,September,October,November,December) 
    )as pvt
Order by Code

但是有一个限制，因为我需要保留所有值，所以没有聚合函数可以在这里工作，即没有 MIN、MAX、SUM 等。使用 Min/Max 将在 value 列中给我 125 或 2250。

所以我的问题是：

有没有一种方法可以通过使用数据透视表找到所需的结果，或者我应该使用#temp 表吗？

4

3 回答 3

0

我知道这是一个非常狭窄的解决方法。它旨在突出将不同月份的数据放在同一行的问题。如果您描述了 ovarall 任务，那么我可以提出更好的解决方案。

Select 
  Code as Code
  Value as May
from Table
where Month = 'May'
于 2013-06-26T11:30:04.880 回答
0

有两种方法可以实现这一点

首先，使用简单的案例:)

SELECT 
Code AS Code,
CASE WHEN Month = 'January' THEN Value ELSE 0 END AS January ,
CASE WHEN Month = 'February' THEN Value ELSE 0 END AS February ,
CASE WHEN Month = 'March' THEN Value ELSE 0 END AS March ,
CASE WHEN Month = 'April' THEN Value ELSE 0 END AS April ,
CASE WHEN Month = 'May' THEN Value ELSE 0 END AS May ,
CASE WHEN Month = 'June' THEN Value ELSE 0 END AS June ,
CASE WHEN Month = 'July' THEN Value ELSE 0 END AS July ,
CASE WHEN Month = 'August' THEN Value ELSE 0 END AS August ,
CASE WHEN Month = 'September' THEN Value ELSE 0 END AS September ,
CASE WHEN Month = 'October' THEN Value ELSE 0 END AS October ,
CASE WHEN Month = 'November' THEN Value ELSE 0 END AS November, 
CASE WHEN Month = 'December' THEN Value ELSE 0 END AS December 
FROM CodePivot1

其次，使用 Pivot 和 Rownum

SELECT Code,
ISNULL(January,0) AS January,
ISNULL(February,0) AS February,
ISNULL(March,0) AS March,
ISNULL(April,0) AS April,
ISNULL(May,0) AS May,
ISNULL(June,0) AS June,
ISNULL(July,0) AS July,
ISNULL(August,0) AS August,
ISNULL(September,0) AS September,
ISNULL(October,0) AS October,
ISNULL(November,0) AS November,
ISNULL(December,0) AS December  
FROM  
    (
    SELECT 
         Code, [Month],  Value, ROW_NUMBER() OVER (ORDER BY Code) [rnum]
    FROM 
        CodePivot1
    )s 
PIVOT 
    (
     MAX([Value])
     FOR [Month]           
     IN (January,February,March,April,May,June,July,August,September,October,November,December) 
)as p
于 2014-07-18T07:23:49.420 回答
0

在我的场景中，使用 Row_number() 将允许获得所需的输出，并且即使有多个月并且一个月的值比其他月多，它也可以处理。希望它可以帮助面临类似情况的人：

Select  
    Code,
    rnum,
    IsNull(January,0)[January(Value)],          
    IsNull(February,0)[February(Value)],              
    IsNull(March,0)[March(Value)],              
    IsNull(April,0)[April(Value)],              
    IsNull(May,0)[May(Value)],              
    IsNull(June,0)[June(Value)],              
    IsNull(July,0)[July(Value)],              
    IsNull(August,0)[August(Value)],              
    IsNull(September,0)[September(Value)],              
    IsNull(October,0)[October(Value)],              
    IsNull(November,0)[November(Value)],              
    IsNull(December,0)[December(Value)]

From 
    (
    Select 
         Code,
        ROW_NUMBER() Over (Order by nSRNo) [rnum],
        [Month],
        Value
    From 
        #tempMonthWiseActualValue
    )s 
Pivot 
    (
     Max([Value] )
     For [Month]           
     In (January,February,March,April,May,June,July,August,September,October,November,December) 
)as pvt
于 2013-06-26T13:21:19.050 回答