22

我已经阅读了其他主题,但它并没有解决我的问题,所以:

我有这个

->add('role', 'choice', array(
                'label' => 'I am:',
                'mapped' => true,
                'expanded' => true,
                'multiple' => false,
                'choices' => array(
                    'ROLE_NORMAL' => 'Standard',
                    'ROLE_VIP' => 'VIP',
                ) 
            ))

无论我做什么,我都会收到这个错误:

Notice: Array to string conversion in C:\xampp\htdocs\xxx\vendor\symfony\symfony  \src\Symfony\Component\Form\Extension\Core\ChoiceList\ChoiceList.php line 458 

在我的表单类型中,甚至没有调用 setRole 方法(当我将它重命名为一些垃圾时,仍然会发生错误)。为什么会这样?

// 编辑

完整的堆栈跟踪:

in C:\xampp\htdocs\xxx\vendor\symfony\symfony\src\Symfony\Component\Form\Extension\Core\ChoiceList\ChoiceList.php at line 458  -

     */
    protected function fixIndex($index)
    {
        if (is_bool($index) || (string) (int) $index === (string) $index) {
            return (int) $index;
        }

    at ErrorHandler ->handle ('8', 'Array to string conversion', 'C:\xampp\htdocs     \xxx\vendor\symfony\symfony\src\Symfony\Component\Form\Extension\Core\ChoiceList\ChoiceList.php', '458', array('index' => array()))
in C:\xampp\htdocs\xxx\vendor\symfony\symfony\src\Symfony\Component\Form\Extension\Core\ChoiceList\ChoiceList.php at line 458  +
at ChoiceList ->fixIndex (array())
in C:\xampp\htdocs\xxx\vendor\symfony\symfony\src\Symfony\Component\Form\Extension\Core\ChoiceList\ChoiceList.php at line 476  +
at ChoiceList ->fixIndices (array(array()))
in C:\xampp\htdocs\xxx\vendor\symfony\symfony\src\Symfony\Component\Form\Extension\Core\ChoiceList\SimpleChoiceList.php at line 152  +
at SimpleChoiceList ->fixChoices (array(array()))
in C:\xampp\htdocs\xxx\vendor\symfony\symfony\src\Symfony\Component\Form\Extension\Core\ChoiceList\ChoiceList.php at line 204  +
at ChoiceList ->getIndicesForChoices (array(array()))
in C:\xampp\htdocs\xxx\vendor\symfony\symfony\src\Symfony\Component\Form\Extension\Core\DataTransformer\ChoiceToBooleanArrayTransformer.php at line 63  +
at ChoiceToBooleanArrayTransformer ->transform (array())
in C:\xampp\htdocs\xxx\vendor\symfony\symfony\src\Symfony\Component\Form\Form.php at line 1019  +
at Form ->normToView (array())
in C:\xampp\htdocs\xxx\vendor\symfony\symfony\src\Symfony\Component\Form\Form.php at line 332  +
at Form ->setData (array())
in C:\xampp\htdocs\xxx\vendor\symfony\symfony\src\Symfony\Component\Form\Extension\Core\DataMapper\PropertyPathMapper.php at line 59  +
at PropertyPathMapper ->mapDataToForms (object(User), object(RecursiveIteratorIterator))
in C:\xampp\htdocs\xxx\vendor\symfony\symfony\src\Symfony\Component\Form\Form.php at line 375  +
at Form ->setData (object(User))
in C:\xampp\htdocs\xxx\vendor\friendsofsymfony\user-bundle\FOS\UserBundle\Controller\RegistrationController.php at line 49  +
at RegistrationController ->registerAction (object(Request))
at call_user_func_array (array(object(RegistrationController), 'registerAction'), array(object(Request)))
in C:\xampp\htdocs\xxx\app\bootstrap.php.cache at line 2770  +
at HttpKernel ->handleRaw (object(Request), '1')
in C:\xampp\htdocs\xxx\app\bootstrap.php.cache at line 2744  +
at HttpKernel ->handle (object(Request), '1', true)
in C:\xampp\htdocs\xxx\app\bootstrap.php.cache at line 2874  +
at ContainerAwareHttpKernel ->handle (object(Request), '1', true)
in C:\xampp\htdocs\xxx\app\bootstrap.php.cache at line 2175  +
at Kernel ->handle (object(Request))
in C:\xampp\htdocs\xxx\web\app_dev.php at line 29  +
4

4 回答 4

39

Symfony 试图将您的 $role(array property) 转换为非多选字段(string)。

有几种方法可以处理这个问题:

  1. 在您的选择表单小部件中将multiple设置为true 。
  2. 将实体中$role属性的映射从数组更改为字符串。
  3. 如果您坚持不更改上述选项,则可以创建 DataTransformer。 这不是最好的解决方案,因为如果您的数组有超过 1 个元素,您丢失数据。

例子:

<?php
namespace Acme\DemoBundle\Form\DataTransformer;

use Symfony\Component\Form\DataTransformerInterface;
use Symfony\Component\Form\Exception\TransformationFailedException;

class StringToArrayTransformer implements DataTransformerInterface
{
    /**
     * Transforms an array to a string. 
     * POSSIBLE LOSS OF DATA
     *
     * @return string
     */
    public function transform($array)
    {
        return $array[0];
    }

    /**
     * Transforms a string to an array.
     *
     * @param  string $string
     *
     * @return array
     */
    public function reverseTransform($string)
    {
        return array($string);
    }
}

然后在您的表单类中:

use Acme\DemoBundle\Form\DataTransformer\StringToArrayTransformer;
/* ... */
$transformer = new StringToArrayTransformer();
$builder->add($builder->create('role', 'choice', array(
                'label' => 'I am:',
                'mapped' => true,
                'expanded' => true,
                'multiple' => false,
                'choices' => array(
                    'ROLE_NORMAL' => 'Standard',
                    'ROLE_VIP' => 'VIP',
                )
              ))->addModelTransformer($transformer));

您可以在此处阅读有关 DataTransformers 的更多信息:http: //symfony.com/doc/current/cookbook/form/data_transformers.html

于 2013-06-27T13:08:32.007 回答
2

确保在 ORM 文件中使用正确的数据类型。在这种情况下,您的角色字段不能是字符串。它必须是多对多关系、数组或 json_array。

如果您选择其中之一,symfony 将毫不费力地插入数据或任何类型的转换器。

例如:

// Resources/config/User.orm.yml
fields:
  role:
      type: array
      nullable: false

因此,它将像这样存在于您的数据库中:

a:2:{i:0;s:4:"user";i:1;s:5:"admin";}
于 2016-01-24T18:48:59.000 回答
1

我只是添加一个 DataTransformer 而不更改我的角色属性的数组类型然后我把它放在我的 UserType 中:

use AppBundle\Form\DataTransformer\StringToArrayTransformer;

//...

$transformer = new StringToArrayTransformer();    
$builder->get('roles')->addModelTransformer($transformer);

它对我有用。

于 2018-02-26T13:49:09.713 回答
0

我有你的问题..我用这个解决方案解决了这个问题。希望对你有帮助

此代码适用于登录和注册表单...

用户实体

class User {
    /**
     * @ORM\Column(type="array")
     */
    private $roles ;

    public function getRoles()
    {
        $roles = $this->roles;
         var_dump($roles);
        if ($roles != NULL) {
            return explode(" ",$roles);
        }else {
           return $this->roles;
        }
    }


  public function setRoles($roles)
    {
        $this->roles = $roles;
    }

用户类型

 ->add('roles', ChoiceType::class, array(
            'attr' => array(
                'class' => 'form-control',
                'value' => $options[0]['roles'],
                'required' => false,
            ),
            'multiple' => true,
            'expanded' => true, // render check-boxes
            'choices' => [
                'admin' => 'ROLE_ADMIN',
                'user' => 'ROLE_USER',
            ]
        ))
于 2018-05-27T17:22:47.277 回答