java - Regex pattern accepting comma separated values

Question

I need a regex pattern that accepts only comma separated values for an input field.

For example: abc,xyz,pqr. It should reject values like: , ,sample text1,text2,

I also need to accept semicolon separated values also. Can anyone suggest a regex pattern for this ?

Answer 1

最简单的形式：

^\w+(,\w+)*$

演示在这里。

---

我只需要限制字母。我怎样才能做到这一点 ？

使用正则表达式（包括示例 unicode 字符范围）：

^[\u0400-\u04FFa-zA-Z ]+(,[\u0400-\u04FFa-zA-Z ]+)*$

这个演示在这里。

示例用法：

public static void main (String[] args) throws java.lang.Exception
{
    String regex = "^[\u0400-\u04FFa-zA-Z ]+(,[\u0400-\u04FFa-zA-Z ]+)*$";

    System.out.println("abc,xyz,pqr".matches(regex)); // true
    System.out.println("text1,text2,".matches(regex)); // false
    System.out.println("ЕЖЗ,ИЙК".matches(regex)); // true
}

Java 演示。

Answer 2

尝试：

^\w+((,\w+)+)?$

您可以使用在线正则表达式测试器进行练习。例如，http://regexpal.com/。

Answer 3

Try the next:

^[^,]+(,[^,]+)*$

You can have spaces between words and Unicode text, like:

word1 word2,áéíóú áéíúó,ñ,word3

Answer 4

The simplest regex that works is:

^\w+(,\w+)*$

And here it is as a method:

public static boolean isCsv(String csv) {
    return csv.matches("\\w+(,\\w+)*");
}

Note that String.matches() doesn't need the start or end regex (^ and $); they are implied with this method, because the entire input must be matched to return true.

Answer 5

我想你想要这个，根据你的评论只想要字母（我假设你的意思是字母）

^[A-Za-z]+(,[A-Za-z]+)*$