4

我想使用 jQuery 根据鼠标位置自动滚动 div。

如果您在这里看到这个小提琴，您可以看到许多在可滚动的 div 中水平排列的图像：

<div id="parent">
    <div id="propertyThumbnails">
        <img src="http://www.millport.org/wp-content/uploads/2013/05/Flower-festival.jpg" />
        <img src="http://www.millport.org/wp-content/uploads/2013/05/Flower-festival.jpg" />
        <img src="http://www.millport.org/wp-content/uploads/2013/05/Flower-festival.jpg" />
        <img src="http://www.millport.org/wp-content/uploads/2013/05/Flower-festival.jpg" />
        <img src="http://www.millport.org/wp-content/uploads/2013/05/Flower-festival.jpg" />
    </div>
</div>

CSS：

#parent {
    height: 300px;
    width: 100%;
    background: #ddd;
}
#propertyThumbnails {
    background: #666;
    height: 80px;
    white-space: nowrap;
    overflow: scroll;
}
#propertyThumbnails img {
    width: 125px;
    height: 80px;
    display: inline-block;
    margin: 3px;
    margin-right: 0;
    opacity: 0.6; 
}

我发现您可以使用$("#container").scrollLeft(position)来设置滚动条的位置，但我想根据父级的鼠标位置来设置。这样当鼠标完全移到右手边时，显示最右边的图像，当鼠标完全离开时，显示最左边的图像。

我怎样才能做到这一点？

4

2 回答 2

8

实现您需要的方式略有不同：

jQuery(function($) {

  $(window).load(function() {

    var $gal = $("#propertyThumbnails"),
      galW = $gal.outerWidth(true),
      galSW = $gal[0].scrollWidth,
      wDiff = (galSW / galW) - 1, // widths difference ratio
      mPadd = 60, // Mousemove Padding
      damp = 20, // Mousemove response softness
      mX = 0, // Real mouse position
      mX2 = 0, // Modified mouse position
      posX = 0,
      mmAA = galW - (mPadd * 2), // The mousemove available area
      mmAAr = (galW / mmAA); // get available mousemove fidderence ratio

    $gal.mousemove(function(e) {
      mX = e.pageX - $(this).offset().left;
      mX2 = Math.min(Math.max(0, mX - mPadd), mmAA) * mmAAr;
    });

    setInterval(function() {
      posX += (mX2 - posX) / damp; // zeno's paradox equation "catching delay"	
      $gal.scrollLeft(posX * wDiff);
    }, 10);

  });

});
#parent {
  position: relative;
  margin: 0 auto;
  width: 60%;
  height: 260px;
}

#propertyThumbnails {
  position: relative;
  overflow: hidden;
  background: #444;
  width: 100%;
  height: 262px;
  white-space: nowrap;
}

#propertyThumbnails img {
  vertical-align: middle;
  height: 100%;
  display: inline;
  margin-left: -4px;
}
<div id="parent">
  <div id="propertyThumbnails">

    <img src="//placehold.it/600x400/0bf" />
    <img src="//placehold.it/600x400/f0b" />
    <img src="//placehold.it/600x400/0fb" />
    <img src="//placehold.it/600x400/b0f" />
    <img src="//placehold.it/600x400/bf0" />

  </div>
</div>


<script src="//ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

区域在哪里mPadd（在 PX 中，在左右边界区域）没有任何敏感性以防止用户沮丧:)

于 2013-06-25T21:52:03.153 回答
2

这至少应该让你朝着正确的方向前进。

var parent = $('#parent');
var img = $('img:first-child');

parent.on('mousemove', function(e) {
    mouseX = e.pageX
    img.css('margin-left',-mouseX/parent.width()*100);

});

http://jsfiddle.net/xWcXt/4/

于 2013-06-25T21:55:46.603 回答