0

我的数据库中有一个表的多个列。我想检查某个列是否有空值。我使用了这段代码，但它只适用于第一个，而不是第二个。

if (!read.IsDBNull(3))
{
  lblInc3.Visible = true;
  txtInc3.Visible = true;
  lblInc3.Text = read["Income3"].ToString();
}
else if (!read.IsDBNull(4))
{
  lblInc4.Visible = true;
  txtInc4.Visible = true;
  lblInc4.Text = read["Income4"].ToString();
} 
else 
{
  txtInc3.Visible = false;
  txtInc4.Visible = false;
}

如果多列没有空值，我只想执行逻辑。如果它有空值，那么文本框不应该是可见的。

编辑：

      try
        {
            SqlConnection sqlCon = new SqlConnection(ConfigurationManager.ConnectionStrings["Connection"].ConnectionString);
            sqlCon.Open();

            SqlCommand com = new SqlCommand("SELECT * FROM Allowance", sqlCon);

            SqlParameter income1 = new SqlParameter("@Income1", SqlDbType.VarChar, 20);
            com.Parameters.Add(income1);
            income1.Direction = ParameterDirection.Output;

            SqlParameter income2 = new SqlParameter("@Income2", SqlDbType.VarChar, 20);
            com.Parameters.Add(income2);
            income2.Direction = ParameterDirection.Output;

            SqlParameter income3 = new SqlParameter("@Income3", SqlDbType.VarChar, 20);
            com.Parameters.Add(income3);
            income3.Direction = ParameterDirection.Output;

            SqlParameter income4 = new SqlParameter("@Income4", SqlDbType.VarChar, 20);
            com.Parameters.Add(income4);
            income4.Direction = ParameterDirection.Output;

            SqlParameter income5 = new SqlParameter("@Income5", SqlDbType.VarChar, 20);
            com.Parameters.Add(income5);
            income5.Direction = ParameterDirection.Output;

            SqlDataReader read = com.ExecuteReader();

            while (read.Read())
            {
                bool threeBool = !read.IsDBNull(1) ? true : false;

                lblInc1.Visible = threeBool;
                txtInc1.Visible = threeBool;
                lblInc1.Text = threeBool ? read["Income1"].ToString() : string.Empty;


                bool fourBool = !read.IsDBNull(4) ? true : false;

                lblInc4.Visible = fourBool;
                txtInc4.Visible = fourBool;
                lblInc4.Text = fourBool ? read["Income4"].ToString() : string.Empty;

                /*if (!read.IsDBNull(1))
                {
                    lblInc1.Visible = true;
                    txtInc1.Visible = true;
                    lblInc1.Text = read["Income1"].ToString();
                }
                else
                {
                    txtInc1.Visible = false;
                }

                if (!read.IsDBNull(2))
                {
                    lblInc2.Visible = true;
                    txtInc2.Visible = true;
                    lblInc2.Text = read["Income2"].ToString();
                }
                else
                {
                    txtInc2.Visible = false;
                }

                if (!read.IsDBNull(3))
                {
                    lblInc3.Visible = true;
                    txtInc3.Visible = true;
                    lblInc3.Text = read["Income3"].ToString();
                }
                else
                {
                    txtInc3.Visible = false;
                }

                if (!read.IsDBNull(4))
                {
                    lblInc4.Visible = true;
                    txtInc4.Visible = true;
                    lblInc4.Text = read["Income4"].ToString();
                }
                else
                {
                    txtInc4.Visible = false;
                }

                if (!read.IsDBNull(5))
                {
                    lblInc5.Visible = true;
                    txtInc5.Visible = true;
                    lblInc5.Text = read["Income5"].ToString();
                }
                else
                {
                    txtInc5.Visible = false;
                }*/
            } catch (Exception ex) {
               throw;
            }
4

3 回答 3

5

它不适用于第二个，因为您使用的是 anelse-if并且在第一个比较评估为 true 后该语句被短路。实施第二个if。例如

if (!read.IsDBNull(3))
{
  lblInc3.Visible = true;
  txtInc3.Visible = true;
  lblInc3.Text = read["Income3"].ToString();
} else
{
   txtInc3.Visible = false;
}

if (!read.IsDBNull(4))
{
  lblInc4.Visible = true;
  txtInc4.Visible = true;
  lblInc4.Text = read["Income4"].ToString();
}  else
{
   txtInc4.Visible = false;
}
于 2013-06-25T12:58:55.440 回答
1

也许是这样的，我希望这会有所帮助（我没有对此进行测试:)）。

编辑：根据您的评论，我相信这就是您想要的。

 bool threeBool = !string.IsNullOrEmpty(read["Income3"].ToString());

  lblInc3.Visible = threeBool ;
  txtInc3.Visible = threeBool ;
  lblInc3.Text = threeBool  ? read["Income3"].ToString() : string.empty;


  bool fourBool = !string.IsNullOrEmpty(read["Income4"].ToString());

  lblInc4.Visible = fourBool ;
  txtInc4.Visible = fourBool ;
  lblInc4.Text = fourBool ? read["Income4"].ToString() : string.empty;
于 2013-06-25T13:10:09.827 回答
0

删除 Else 部分，如果第一个为 True，则跳过 Else 部分...

if (!read.IsDBNull(3))
{
  lblInc3.Visible = true;
  txtInc3.Visible = true;
  lblInc3.Text = read["Income3"].ToString();
}

if (!read.IsDBNull(4))
{
  lblInc4.Visible = true;
  txtInc4.Visible = true;
  lblInc4.Text = read["Income4"].ToString();
}
于 2013-06-25T13:00:27.803 回答