php - Mysql WHERE NOT EXISTS（查询）或（查询）

Question

是否可以编写一个查询来检查任一子查询是否正确而不是一个？

SELECT  *
FROM    employees e
WHERE   NOT EXISTS
        (
        SELECT  null 
        FROM    eotm_dyn d
        WHERE   d.employeeID = e.id
        ) OR (select * FROM table c WHERE c.employeeID = e.id)

Answer 1

是的，只需将该OR条件更改为另一个EXISTS表达式：

SELECT  *
FROM    employees e
WHERE   NOT EXISTS
           (
             SELECT  null 
             FROM    eotm_dyn d
             WHERE   d.employeeID = e.id
           ) 
    AND NOT EXISTS
           (
             select null
             FROM   table c
             WHERE  c.employeeID = e.id
           )

也猜测你的意图。这将检查两个子查询的记录是否不存在。如果您要检查一个或另一个，我不确定您的意思。

更新：再次尝试想象，也许您打算做一个OR EXISTS：

SELECT  *
FROM    employees e
WHERE   NOT EXISTS
           (
             SELECT  null 
             FROM    eotm_dyn d
             WHERE   d.employeeID = e.id
           ) 
     OR EXISTS
           (
             select null
             FROM   table c
             WHERE  c.employeeID = e.id
           )

这将在employees其中找到不在或不在的记录。eotm_dyntable

Answer 2

你的问题有点难以理解，但我猜这就是你所要求的。它将返回employees表中没有任何相关行的表eotm_dyn和table.

SELECT  *
FROM    employees e
WHERE  e.id NOT IN
    (
        (SELECT  employeeID 
        FROM    eotm_dyn)
     UNION
        (SELECT employeeID 
        FROM table)
    )