我想通过 ajax 滚动使转发器数据可滚动，就像 facebook 在新闻提要中所做的那样，这是我的代码，请帮助我，我希望通过页面滚动获取所有这些。
ASPX 页面
<form id="form1" runat="server">
<asp:Repeater ID="RepDetails" runat="server">
<HeaderTemplate>
<table style=" border:1px solid #df5015; width:500px" cellpadding="0">
<tr style="background-color:#df5015; color:White">
<td colspan="2">
<b>Comments</b>
</td>
</tr>
</HeaderTemplate>
<ItemTemplate>
<tr style="background-color:#EBEFF0">
<td>
<table style="background-color:#EBEFF0;border-top:1px dotted #df5015; width:500px" >
<tr>
<td>
Subject:
<asp:Label ID="lblSubject" runat="server" Text='<%#Eval("Subject") %>' Font-Bold="true"/>
</td>
</tr>
</table>
</td>
</tr>
<tr>
<td>
<asp:Label ID="lblComment" runat="server" Text='<%#Eval("Comment") %>'/>
</td>
</tr>
<tr>
<td>
<table style="background-color:#EBEFF0;border-top:1px dotted #df5015;border-bottom:1px solid #df5015; width:500px" >
<tr>
<td>Post By: <asp:Label ID="lblUser" runat="server" Font-Bold="true" Text='<%#Eval("UserName") %>'/></td>
<td>Created Date:<asp:Label ID="lblDate" runat="server" Font-Bold="true" Text='<%#Eval("PostedDate") %>'/></td>
</tr>
</table>
</td>
</tr>
<tr>
<td colspan="2"> </td>
</tr>
</ItemTemplate>
</table>
</asp:Repeater>
文件后面的代码
protected void Page_Load(object sender, EventArgs e)
{
if(!IsPostBack)
{
BindRepeaterData();
}
}
//Bind Data to Repeater Control
protected void BindRepeaterData()
{
con.Open();
SqlCommand cmd = new SqlCommand("select * from Repeater_Table Order By PostedDate desc", con);
DataSet ds = new DataSet();
SqlDataAdapter da = new SqlDataAdapter(cmd);
da.Fill(ds);
RepDetails.DataSource = ds;
RepDetails.DataBind();
con.Close();
}
请帮助我，我希望通过页面滚动获取所有这些内容。