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我尝试编写一个简单的循环，它使用 GetSegmentAttr 来获取当前段的开始和结束，然后假设当前段的结束将是下一个段的开始，但这个假设是错误的。它适用于几个细分市场，但我发现细分市场之间可能存在差距。

所以，我想知道的是如何可靠地迭代所有的细分？

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2 回答 2

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您可以迭代以下结果idautils.Segments()：

for seg in idautils.Segments():
    # ...
于 2013-06-24T17:52:00.270 回答
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像这样使用 FirstSeg() 和 NextSeg()

#include <idc.idc>

static main() {
    auto seg;
    auto start;
    auto end; 

    seg = FirstSeg();

    while(seg != BADADDR)
    {
        start = SegStart(seg);
        end = SegEnd(seg);

        Message("Seg: %a Start: %a End: %a\n", seg, start, end);

        // do looping here

        seg = NextSeg(seg);
    }
}

然后将变量从“开始”循环到包括“结束”

对于我目前的项目，上面给出了：

Seg: ROM:00000000 Start: ROM:00000000 End: ROM2:00880000
Seg: ROM2:00880000 Start: ROM2:00880000 End: 0:009FFFFF
Seg: CHIP:40000000 Start: CHIP:40000000 End: 0:4004FFFF
Seg: CHIP:40050000 Start: CHIP:40050000 End: 0:4005FFFF
Seg: CHIP:40070000 Start: CHIP:40070000 End: 0:4007FFFF
Seg: CHIP:40130000 Start: CHIP:40130000 End: 0:4013FFFF
Seg: CHIP:40180000 Start: CHIP:40180000 End: 0:4018FFFF
Seg: CHIP:401D0000 Start: CHIP:401D0000 End: 0:401DFFFF
Seg: CHIP:50000000 Start: CHIP:50000000 End: 0:5001FFFF
Seg: s6800:68000000 Start: s6800:68000000 End: 0:6800FFFF
Seg: CHIP:6F000000 Start: CHIP:6F000000 End: 0:6F00FFFF
Seg: RAM:8F800000 Start: RAM:8F800000 End: 0:8F9FFFFF
Seg: RAM:8FB00000 Start: RAM:8FB00000 End: 0:8FFFFFFF
Seg: RAM:CD000000 Start: RAM:CD000000 End: 0:CEFFFFFF
于 2013-10-10T02:24:11.137 回答