0 
  SELECT 
        BB.NAME BranchName,
        VI.NAME Village,
        COUNT(BAC.CBSACCOUNTNUMBER) 'No.Of Accounts',
        SUM(BAC.CURRENTBALANCE) SumOfAmount,
        SUM(CASE
            WHEN transactiontype = 'C' THEN amount
            ELSE 0
        END) AS CreditTotal,
        SUM(CASE
            WHEN transactiontype = 'D' THEN amount
            ELSE 0
        END) AS DebitTotal,
        SUM(CASE
            WHEN transactiontype = 'C' THEN amount
            WHEN transactiontype = 'D' THEN - 1 * amount
            ELSE 0
        END) AS CurrentBalance
    FROM
        CUSTOMER CU,
        APPLICANT AP,
        ADDRESS AD,
        VILLAGE VI,
        BANKBRANCH BB,
        BANKACCOUNT BAC
            LEFT OUTER JOIN
        accounttransaction ACT ON BAC.CBSACCOUNTNUMBER = ACT.BANKACCOUNT_CBSACCOUNTNUMBER
            AND ACT.TRANDATE <= '2013-03-21'
            AND BAC.ACCOUNTOPENINGDATE < '2013-03-21'
            AND ACT.BANKACCOUNT_CBSACCOUNTNUMBER IS NOT NULL
    WHERE
        CU.CODE = AP.CUSTOMER_CODE
            AND BAC.ENTITY = 'CUSTOMER'
            AND BAC.ENTITYCODE = CU.CODE
            AND AD.ENTITY = 'APPLICANT'
            AND AD.ENTITYCODE = AP.CODE
            AND AD.VILLAGE_CODE = VI.CODE
            AND AD.STATE_CODE = VI.STATE_CODE
            AND AD.DISTRICT_CODE = VI.DISTRICT_CODE
            AND AD.BLOCK_CODE = VI.BLOCK_CODE
            AND AD.PANCHAYAT_CODE = VI.PANCHAYAT_CODE
            AND CU.BANKBRANCH_CODE = BB.CODE
            AND BAC.CBSACCOUNTNUMBER IS NOT NULL
            AND ACT.TRANSACTIONTYPE IS NOT NULL
    GROUP BY BB.NAME , VI.NAME;

这是我的信息，我有两个表 bankaccount 和 accountransactions 表如果创建了帐户，它将转到 bankaccount 表，并且如果进行了任何交易，那么 accounttrasactiosns 表中的相应帐号记录但是我想显示相对于总帐号的计数帐号存在于银行账户中的分行，它在 accounttransactions 表中可能可用也可能不可用。

4

1 回答 1

0

我猜您遇到的问题是您没有为accounttransaction表中没有数据的帐户获得结果，即使您使用的是LEFT JOIN. 如果这是真的，原因是因为您的加入条件包括AND ACT.BANKACCOUNT_CBSACCOUNTNUMBER IS NOT NULL，它击败了LEFT JOIN. 您的WHERE条款中还有两个条件，我打赌不应该存在。

您应该学习在编码中使用显式连接语法。如果你这样做，你的代码会更清晰；它将连接条件与WHERE子句分开，后者做了非常不同的事情。我尝试重新编写您的查询作为说明：

SELECT
    BB.NAME BranchName,
    VI.NAME Village,
    COUNT(BAC.CBSACCOUNTNUMBER) 'No.Of Accounts',
    SUM(BAC.CURRENTBALANCE) SumOfAmount,
    SUM(ACT.CurrentBalance) CurrentBalance,
    SUM(ACT.DebitTotal) DebitTotal,
    SUM(ACT.CreditTotal) CreditTotal

FROM   CUSTOMER CU

JOIN   APPLICANT AP
ON     AP.CUSTOMER_CODE = CU.CODE

JOIN   ADDRESS AD
ON     AD.ENTITYCODE = AP.CODE

JOIN   VILLAGE VI
ON     VI.CODE           = AD.VILLAGE_CODE
   AND VI.STATE_CODE     = AD.STATE_CODE
   AND VI.DISTRICT_CODE  = AD.DISTRICT_CODE
   AND VI.BLOCK_CODE     = AD.BLOCK_CODE
   AND VI.PANCHAYAT_CODE = AD.PANCHAYAT_CODE

JOIN   BANKBRANCH BB
ON     BB.CODE = CU.BANKBRANCH_CODE

JOIN   BANKACCOUNT BAC
ON     BAC.ENTITYCODE = CU.CODE

LEFT OUTER JOIN (
   SELECT BANKACCOUNT_CBSACCOUNTNUMBER,
          SUM(CASE
             WHEN transactiontype = 'C' THEN amount
             ELSE 0
             END) AS CreditTotal,
          SUM(CASE
             WHEN transactiontype = 'D' THEN amount
             ELSE 0
             END) AS DebitTotal,
          SUM(CASE
             WHEN transactiontype = 'C' THEN amount
             WHEN transactiontype = 'D' THEN - 1 * amount
             ELSE 0
             END) AS CurrentBalance
   FROM    accounttransaction
   WHERE   TRANDATE <= '2013-03-21'
   GROUP BY BANKACCOUNT_CBSACCOUNTNUMBER
   ) ACT

ON     ACT.BANKACCOUNT_CBSACCOUNTNUMBER = BAC.CBSACCOUNTNUMBER
   AND BAC.ACCOUNTOPENINGDATE < '2013-03-21'

WHERE  BAC.ENTITY = 'CUSTOMER'
   AND AD.ENTITY = 'APPLICANT'

GROUP BY BB.NAME , VI.NAME;

我从LEFT JOIN条件中删除了这一行

AND ACT.BANKACCOUNT_CBSACCOUNTNUMBER IS NOT NULL

我从 WHERE 子句中删除了这两行

AND BAC.CBSACCOUNTNUMBER IS NOT NULL
AND ACT.TRANSACTIONTYPE IS NOT NULL

如果这不能解决您的问题，请修改您的问题以进一步解释。

更新：根据评论，修改查询以使用派生表按帐户计算借方、贷方和当前余额。

还要注意BAC.ACCOUNTOPENINGDATE < '2013-03-21'左连接上条件的位置。如所写，无论开户日期如何，这将返回所有帐户。如果您只想显示在该日期之前开设的帐户，则应将此条件移至该WHERE子句。

于 2013-06-24T15:54:47.530 回答