-1

当我在一个 Java 应用程序上按“Enter”键时，我正在尝试制作一个示例代码来提交一个文本字段。

我正在使用 JFrame 和以下代码：

package com.sh.st;

import java.awt.Color;
import java.awt.GridLayout;
import java.awt.event.KeyEvent;

import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.JTextField;




public class SearchScreen extends JFrame{

    JButton btsearch;
    JLabel lbsearch;
    JTextField txtsearch;
    JPanel p1;

    public SearchScreen(){

    //Button Creation
    btsearch= new JButton("Search");


    //Label Creation
    lbsearch= new JLabel("Type Keywords in english to be searched below:");


    //TextBox   
    txtsearch= new JTextField();


    //Pane Creation 
    p1=new JPanel();
    p1.setBackground(Color.gray);

    //Pane Components
    p1.add(lbsearch);
    p1.add(txtsearch);
    p1.add(btsearch);

    btsearch.setEnabled(true);

    //Adding JPaneel    
    getContentPane().add(p1);

    //JFrame Setup
    setSize(300,300);
    setTitle("SHST");

    //JFrame Layout Setup   
    p1.setLayout(new GridLayout(3,3));


    btsearch.setMnemonic(KeyEvent.VK_ENTER);

    }

}

但问题是，作为一个虚拟键，我需要同时按住“alt”，这对于用户来说太不舒服了，也不直观。

我试图查看堆栈和谷歌的很多页面，但没有一个给我答案。我看到了一些命令，例如“addKeyListener”，但直到现在我才能做到我想要的。

谢谢您的帮助

编辑[主题已解决]：

    package com.sh.st;

import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.io.IOException;

import javax.swing.AbstractAction;
import javax.swing.Action;
import javax.swing.JOptionPane;
import javax.swing.KeyStroke;


public class EventSearch extends SearchScreen{

    String query;



    public EventSearch(){

        txtsearch.getInputMap().put(keyStroke, key);
        txtsearch.getActionMap().put(key, enterAction);


}

    Action enterAction = new AbstractAction() {
        @Override
        public void actionPerformed(ActionEvent e) {
            try {

                HttpRequest http = new HttpRequest(CatchQuery());

                } catch (IOException e1) {
                e1.printStackTrace(); //print failure
                JOptionPane.showMessageDialog(null, "HTTP request failure.");
            }   
        }};
     String key = "ENTER";
     KeyStroke keyStroke = KeyStroke.getKeyStroke(key);



            public String CatchQuery(){
                query=txtsearch.getText();
                this.dispose();
                return query;
            }



}
4

2 回答 2

2

您可以使用KeyBindings 如何使用 KeyBindings

这是一段代码

final JTextField textfield = new JTextField();
Action enterAction = new AbstractAction() {
    @Override
    public void actionPerformed(ActionEvent e) {
        //do something
    }};
 String key = "ENTER";
 KeyStroke keyStroke = KeyStroke.getKeyStroke(key);
 textfield.getInputMap().put(keyStroke, key);
 textfield.getActionMap().put(key, enterAction);
于 2013-06-24T13:02:36.130 回答
0

只需将 ActionListener 添加到您的文本字段：

//TextBox   
txtsearch = new JTextField();
txtsearch.addActionListener(new ActionListener() {
  @Override
  public void actionPerformed(ActionEvent e) {
    // code when enter is pressed in text field
  }
});
于 2013-06-24T13:39:17.540 回答