Employee (table)
id - int
ctd_id - int
message - char
SELECT a.*
FROM Employee a left outer join
( select * from Employee where message = 23 ) b
on a.ctd_id = b.ctd_id
where a.message = 22 and b.id is null;
这是我试过的
CriteriaBuilder cb = entityManager.getCriteriaBuilder();
CriteriaQuery<Employee> criteria = cb.createQuery(Employee.class);
Root<Employee> emp = criteria.from(Employee.class);
CriteriaQuery<Employee> sq = c.select(emp);
Subquery<Employee> sq2 = criteria.subquery(Employee.class);
Root<Employee> emp2 = sq2.from(Employee.class);
Join<Employee,Employee> sqEmp = emp2.join("ctd_id", JoinType.LEFT);
sq.select(sqemp).where(cb.equal(emp2.get("message"), cb.parameter(String.class, "23")));
sq.where(cb.in(path).value(sq2));
TypedQuery<Employee> q = em.createQuery(criteria);
List<Employee> employeess = q.getResultList()
但是，我无法理解我应该如何在带有 where 子句的子查询上应用连接。
请帮忙 。