I want to display first 20 records from collection on one Jframe and next 20 on another frame . I am newbie to MongoDB. please suggest a query to find first 20 and next 20 documents.
问问题
15217 次
3 回答
13
在 MongoDB shell 上,您可以执行以下操作:
db.collectionName.find( { city: "London" } ).skip( 20 ).limit( 20 );
显示文档 21 到 40 的结果。
请查看限制并跳过:http ://docs.mongodb.org/manual/core/read/#limit-the-number-of-documents-to-return
我还强烈建议您阅读教程:http ://docs.mongodb.org/manual/tutorial/getting-started/
于 2013-06-24T08:05:54.640 回答
1
这是我到目前为止所取得的成就
function getFirst20Items() {
let items
ITEMS_COLLECTION
.find({})
.limit(20)
.sort({id: 1})
.toArray( (err, allItems) => {
items = allItems
})
return new Promise(resolve => {
setTimeout(() => {
resolve(items)
}, 2000)
})
}
function getSecond20Items() {
let items
ITEMS_COLLECTION
// gte stands for --> Greater than
.find({ id: { $gte: 20 } })
.limit(20)
.sort({id: 1})
.toArray( (err, allItems) => {
items = allItems
})
return new Promise(resolve => {
setTimeout(() => {
resolve(items)
}, 2000)
})
}
app.get('/first/40/products', (req, res) => {
const all_Items = []
getFirst20Items()
.then(items => {
all_Items.push(...items)
})
.catch(err => {
throw new CustomError('Could not get Items', err);
});
getSecond20Items()
.then(items => {
all_Items.push(...items)
})
.catch(err => {
throw new CustomError('Could not get Items', err);
});
setTimeout(() => {
res.send(all_Items);
}, 2000);
});
你可以在你的逻辑中从这里继续
希望这可以帮助
于 2019-03-25T10:55:50.903 回答
0
db.getCollection('name of your collection').find({}).limit(20)
于 2017-10-26T10:09:23.073 回答