我有一个要求,我使用 -D 选项传递属性+值。我想访问 pom.xml 文件中的值。你能帮我知道我怎样才能达到同样的效果吗?
例如:-Dname="BlaBla"
现在在 pom.xml 文件中如何获取“名称”的值?感谢你的帮助。
The handling of properties in maven is described here: POM Reference -> Properties
In your case just use: ${name}
Example:
pom.xml
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>property-test</groupId>
<artifactId>property-test</artifactId>
<version>1.0-SNAPSHOT</version>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-antrun-plugin</artifactId>
<version>1.7</version>
<executions>
<execution>
<phase>validate</phase>
<goals>
<goal>run</goal>
</goals>
<configuration>
<target>
<echo>Value of FooBar is: ${FooBar}</echo>
</target>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</build>
</project>
Call:
mvn validate -DFooBar="Hello World"
Result:
[echo] Value of FooBar is: Hello World