2

以下...

class TestClass
{
public:

    TestClass(const char* szParam, int nParam)
    : m_strParam(szParam)
    , m_nParam(nParam)
    {
        Dbg_Printf("2 param constructor - %s, %d\n", m_strParam.c_str(), m_nParam);
    }

    TestClass()
    : m_strParam("Default")
    , m_nParam(0)
    {
        Dbg_Printf("0 param constructor - %s, %d\n", m_strParam.c_str(), m_nParam);
    }

    virtual ~TestClass()
    {
        Dbg_Printf("Destructor - %s, %d\n", m_strParam.c_str(), m_nParam);
        m_strParam.clear();
        m_nParam = 0;
    }

    std::string m_strParam;
    int m_nParam;
};


void Test()
{
    Dbg_Printf("Start\n");
    {
        Dbg_Printf("Allocating 0 param TestClass\n");
        auto pTest_0Params = std::make_shared<TestClass>();
        Dbg_Printf("Done allocating, going out of scope\n");
    }

    {
        Dbg_Printf("Allocating 2 param TestClass\n");
        const char* szTest = "2 param";
        int foo = 2;
        auto pTest_2Params = std::make_shared<TestClass>(szTest, foo);
        Dbg_Printf("Done allocating, going out of scope\n");
    }
    Dbg_Printf("Done\n");
}

产生以下结果

Start
Allocating 0 param TestClass
0 param constructor - Default, 0
Done allocating, going out of scope
Destructor - Default, 0
Allocating 2 param TestClass
2 param constructor - 2 param, 2
Destructor - 2 param, 2
Destructor - 2 param, 2
Done allocating, going out of scope
Destructor - 2 param, 2
Done

对 make_shared 的 2 参数调用最终在分配和分配它时调用了析构函数两次。

我用析构函数中的断点一次又一次地调试了这个。在 2 参数情况下，它位于 make_shared 调用的中间。

看不到代码有任何明显错误。还有人看到这个吗？想法？

4

1 回答 1

2

你有-std=c++11指定吗？

当我在桌面上编译时：

clang++ -std=c++03 -stdlib=libc++ test.cpp

我得到你得到的：

Start
Allocating 0 param TestClass
0 param constructor - Default, 0
Done allocating, going out of scope
Destructor - Default, 0
Allocating 2 param TestClass
2 param constructor - 2 param, 2
Destructor - 2 param, 2
Destructor - 2 param, 2
Done allocating, going out of scope
Destructor - 2 param, 2
Done

但是当我打开时，-std=c++11我得到：

Start
Allocating 0 param TestClass
0 param constructor - Default, 0
Done allocating, going out of scope
Destructor - Default, 0
Allocating 2 param TestClass
2 param constructor - 2 param, 2
Done allocating, going out of scope
Destructor - 2 param, 2
Done
于 2013-06-24T15:08:20.507 回答