当我按下按钮时,我的 C# 代码中出现以下错误。它被我的 try-catch 捕获:
MySql.Data.dll 中发生了“MySql.Data.MySqlClient.MySqlException”类型的第一次机会异常
我想知道这可能是什么问题。任何帮助表示赞赏!
方法:
private void addChildBtn_Click(object sender, EventArgs e)
{
string firstName = firstNameAdd.Text;
int ageComboIndex = ageComboAdd.SelectedIndex;
string age = this.ageComboAdd.Items[ageComboIndex].ToString();
int genderComboIndex = genderComboAdd.SelectedIndex;
string gender = this.genderComboAdd.Items[genderComboIndex].ToString();
string address = addressAdd.Text;
string caregiverOneName = caregiver1NameAdd.Text;
string caregiverOnePhone = caregiver1PhoneAdd.Text;
string caregiverTwoName = caregiver2NameAdd.Text;
string caregiverTwoPhone = caregiver2PhoneAdd.Text;
server = "localhost";
port = "3306";
database = "childeren";
uid = "root";
password = "password";
MySqlConnection connection2 = new MySqlConnection("Server=" + server + ";" +
"Port=" + port + ";" + "Database=" + database + ";" +
"Uid=" + uid + ";" + "Password=" + password + ";");
// Perform databse operations
try
{
connection2.Open();
string query = "INSERT INTO childdatabase (name2, age, gender, " +
"adress, caregiver1Name, caregiver1Phone, caregiver2Name, " +
"caregiver2Phone) VALUES('" + firstName + "','" + age +
"','" + gender + "','" + address + "','" + caregiverOneName +
"','" + caregiverOnePhone + "','" + caregiverTwoName +
"','" + caregiverTwoPhone + "')";
MySqlCommand cmd = new MySqlCommand(query, connection2);
cmd.ExecuteNonQuery();
connection2.Close();
}
catch (Exception ex)
{
MessageBox.Show("Failed");
//updateStatus(ex.Message.ToString());
}
connection2.Close();
}
MySQL CREATE 表设置:
create database childeren;
use childeren;
CREATE TABLE childDatabase
(
id INT(10) UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
name2 VARCHAR(50),
age VARCHAR(3),
gender VARCHAR(6),
adress VARCHAR(50),
caregiver1Name VARCHAR(50),
caregiver1Phone VARCHAR(10),
caregiver2Name VARCHAR(50),
caregiver2Phone VARCHAR(10)
);