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这是我显示当前网页网址的代码。该代码工作正常，但我只想从 url 获取特定值。

我关注这篇文章，但对我没有帮助。代码在运行时爆炸。浏览Playstore时我只想要ID

    public class WebViewClientDemoActivity extends Activity {
    /** Called when the activity is first created. */

    WebView web;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        web = (WebView) findViewById(R.id.webview01);
        web.setWebViewClient(new myWebClient());
        web.getSettings().setJavaScriptEnabled(true);
        web.loadUrl("https://play.google.com/store/apps");
    }

    public class myWebClient extends WebViewClient
    {
        @Override
        public void onPageStarted(WebView view, String url, Bitmap favicon) {
            // TODO Auto-generated method stub
            super.onPageStarted(view, url, favicon);
        }

        @Override
        public boolean shouldOverrideUrlLoading(WebView view, String url) {
            // TODO Auto-generated method stub
            String[] splited =  url.split("&");
            String[] id = splited[0].split("?id=");
            Toast.makeText (getApplicationContext(), id.toString(), 
              Toast.LENGTH_SHORT).show ();

            view.loadUrl(url);

            return true;
        // this is example url i just want to get only id from which url
        //https://play.google.com/store/apps/details?id=com.eamobile.monopoly_row_wf&feature
        //=more_from_developer#?t=W251bGwsMSwyLDEwMiwiY29tLmVhbW9iaWxlLm1vbm9wb2x5X3Jvd193ZiJd

        }
    }

    // To handle "Back" key press event for WebView to go back to previous screen.
    @Override
    public boolean onKeyDown(int keyCode, KeyEvent event) 
    {
        if ((keyCode == KeyEvent.KEYCODE_BACK) && web.canGoBack()) {
            web.goBack();
            return true;
        }
        return super.onKeyDown(keyCode, event);
    }
}
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1 回答 1

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正如您在评论中提到的，您希望看到com.eamobile.monopoly_row_wf

因此，代码是

 String standard = "https://play.google.com/store/apps/details?id=";
 String id= url.substring(standard.length(), url.indexOf("&"));
 Toast.makeText (getApplicationContext(), id.toString(), Toast.LENGTH_SHORT).show ();
于 2013-06-23T18:14:19.380 回答