2

这很奇怪。

我创建了一个 django 模型的实例并将其保存到数据库中，但是当我再次回忆它时，值位于错误的列中。我尝试将代码移到另一台机器上，以为我可能有一些库配置错误，但在那里也失败了。我做了一些广泛的谷歌搜索，但没有发现任何与我类似的问题。

这是模型定义：（__init__如果重要，请定义）

class Buffer(models.Model):
    b_bname = models.CharField(max_length=60)
    b_tdate = models.DateField() # date of transaction
    b_bdate = models.DateField() # date at bank
    b_bamnt = models.FloatField()
    b_descript = models.CharField(max_length=120)
    b_kind = models.CharField(max_length=12)
    b_account = models.CharField(max_length=40)

    def __init__(self, name, *args, **kwargs):
        super(Buffer, self).__init__(*args, **kwargs)
        self.b_bname = name

下面是一个失败的例子：

% python manage.py shell
Python 2.7.3 (default, Aug  4 2012, 18:36:39) 
[GCC 4.2.1 20070831 patched [FreeBSD]] on freebsd9
Type "help", "copyright", "credits" or "license" for more information.
(InteractiveConsole)
>>> from buffer.models import Buffer
>>> b = Buffer('schwab')
>>> b.b_tdate = '2008-11-03'
>>> b.b_bdate = '2009-01-20'
>>> b.b_bamnt = 3.1415
>>> b.b_descript = 'easy as pi'
>>> b.b_kind = 'POS'
>>> b.b_account = 'groceries'
>>> b.save()
(0.002) INSERT INTO "buffer_buffer" ("b_bname", "b_tdate", "b_bdate", "b_bamnt", "b_descript", "b_kind", "b_account") VALUES (schwab, 2008-11-03, 2009-01-20, 3.1415, easy as pi, POS, groceries); args=['schwab', u'2008-11-03', u'2009-01-20', 3.1415, 'easy as pi', 'POS', 'groceries']
(0.002) INSERT INTO "buffer_buffer" ("b_bname", "b_tdate", "b_bdate", "b_bamnt", "b_descript", "b_kind", "b_account") VALUES (schwab, 2008-11-03, 2009-01-20, 3.1415, easy as pi, POS, groceries); args=['schwab', u'2008-11-03', u'2009-01-20', 3.1415, 'easy as pi', 'POS', 'groceries']
>>> b.pk                  
1
>>> c = Buffer.objects.get(pk=1)
(0.000) SELECT "buffer_buffer"."id", "buffer_buffer"."b_bname", "buffer_buffer"."b_tdate", "buffer_buffer"."b_bdate", "buffer_buffer"."b_bamnt", "buffer_buffer"."b_descript", "buffer_buffer"."b_kind", "buffer_buffer"."b_account" FROM "buffer_buffer" WHERE "buffer_buffer"."id" = 1 ; args=(1,)
(0.000) SELECT "buffer_buffer"."id", "buffer_buffer"."b_bname", "buffer_buffer"."b_tdate", "buffer_buffer"."b_bdate", "buffer_buffer"."b_bamnt", "buffer_buffer"."b_descript", "buffer_buffer"."b_kind", "buffer_buffer"."b_account" FROM "buffer_buffer" WHERE "buffer_buffer"."id" = 1 ; args=(1,)
>>> c.b_bname
1
>>> c.b_tdate
datetime.date(2009, 1, 20)
>>> c.b_bdate
3.1415
>>> c.b_bamnt
u'easy as pi'
>>> c.b_kind
u'groceries'
>>> c.b_account
''
>>> 
% sqlite3 register 
SQLite version 3.7.13 2012-06-11 02:05:22
Enter ".help" for instructions
Enter SQL statements terminated with a ";"
sqlite> select count(id) from buffer_buffer;
1
sqlite> select b_bamnt from buffer_buffer;
3.1415

如您所见，数据库是正确的，但检索到的对象是错误的。我哪里搞砸了？我一定有一个错误在这里的某个地方。我已经追了一天多了，现在。

环境：Python 2.7，Django 1.4，sqlite 3.7作为后端，FreeBSD 9.0

4

1 回答 1

3

不要更改模型__init__方法的类型签名以获取name参数。它不仅在您在 shell 中创建实例时调用，而且在初始化实例时调用，包括从数据库中获取时。

当您可以使用命名参数时，不清楚为什么需要重写该__init__方法，如下所示：

b = 缓冲区（名称='schwab'）

如果您在创建新实例时需要一种方便的方法，请考虑使用 create 方法创建自定义管理器。以User.objects.create_user()方法为例，它负责对密码进行哈希处理。

于 2013-06-23T20:46:17.510 回答