6

在以下查询中，我想要等价于

GROUP_CONCAT(ctAncestors.ancestor ORDER BY ctAncestors.depth DESC) AS breadcrumbs_id

在火鸟。

到目前为止我得到了

LIST(ctAncestors.ancestor, ',') AS breadcrumbs_id

我无法弄清楚如何在 list 指令中添加 order by。

如何在列表聚合中进行排序？

-- http://www.unlimitedtricks.com/sorting-a-subtree-in-a-closure-table-hierarchical-data-structure/

-- DECLARE @__in_rootnodeId AS bigint 
-- SET @__in_rootnodeId = 8 
-- SET @__in_rootnodeId = 1 


SELECT 
     COALESCE(ctDescendants.ancestor, 0) AS parent_id 
    ,ctAncestors.descendant AS child_id 
    ,tClosureItemsTable.COM_Id 
    ,tClosureItemsTable.COM_Text 

--,'ab' as breadcrumbs
 
--,LIST(ctAncestors.ancestor ORDER BY ctAncestors.depth DESC) AS breadcrumbs_id 
,LIST(ctAncestors.ancestor, ',') AS breadcrumbs_id 
    --,GROUP_CONCAT(ctAncestors.ancestor ORDER BY ctAncestors.depth DESC) AS breadcrumbs_id 
    -- ,GROUP_CONCAT(breadcrumb_data.COM_Text ORDER BY ctAncestors.depth DESC) AS breadcrumbs 
--,GROUP_CONCAT(breadcrumb_data.COM_Text ORDER BY ctAncestors.depth) AS breadcrumbs 
,LIST(breadcrumb_data.COM_Text) AS breadcrumbs 
--,GROUP_CONCAT(breadcrumb_data.COM_Text ORDER BY ctAncestors.depth DESC SEPARATOR '-') AS breadcrumbs2 




/*  
,
    SUBSTRING
    (
        (
            SELECT 
                -- breadcrumb.ancestor AS 'text()'  -- Remove substring for this 
                -- ', ' + CAST(breadcrumb.ancestor AS nvarchar(36)) AS 'text()'
                ', ' + CAST(breadcrumb_data.comment AS nvarchar(36)) AS 'text()'
            FROM T_CommentClosure AS breadcrumb 
            
            LEFT JOIN Comments AS breadcrumb_data
                ON breadcrumb_data.COM_Id = breadcrumb.ancestor

            WHERE (breadcrumb.descendant = ctAncestors.descendant) 

            ORDER BY breadcrumb.depth DESC
            FOR XML PATH('')
        )
        ,2
        ,8000
    ) AS breadcrumbs 
*/  

    ,
    (
        SELECT COUNT(*) FROM T_CommentClosure AS tp 
        WHERE tp.ancestor = tClosureItemsTable.COM_Id AND tp.depth = 1 
    ) AS ChildCount 

FROM T_CommentClosure AS ctAncestors  

-- Must be left join, for root node
LEFT JOIN T_CommentClosure AS ctDescendants 
    ON (ctDescendants.descendant = ctAncestors.descendant) 
    AND (ctDescendants.depth = 1) 

-- INNER JOIN just in case item has been somehow deleted when FK disabled 
INNER JOIN T_Comments AS tClosureItemsTable  
    ON (ctAncestors.descendant = tClosureItemsTable.COM_Id) 
    
INNER JOIN T_Comments AS breadcrumb_data
    ON breadcrumb_data.COM_Id = ctAncestors.ancestor 
    
WHERE (1=1) 
-- AND (ctAncestors.ancestor = @__in_rootnodeId) -- ROOT node id 
AND 
( 
    -- ( ctAncestors.ancestor = @__in_rootnodeId) -- ROOT node id 
    (1=2) 
    OR 
    (1=1)
--    (@__in_rootnodeId IS NULL) 
) 

-- AND tClosureItemsTable.active = 1 

GROUP BY 
     ctAncestors.descendant 
    ,ctDescendants.ancestor 
    ,tClosureItemsTable.COM_Id 
    ,tClosureItemsTable.COM_Text 

ORDER BY breadcrumbs ASC  -- DESC
4

2 回答 2

8

作为LIST()国家的文件：

列表值的顺序未定义。

也就是说，如果您使用首先按GROUP BY-columns 和此列排序的子查询或公用表表达式 (CTE)，那么它将起作用，但这确实意味着您依赖于可能会随着点发布或新版本而改变的实现人工制品版本。

Firebird 跟踪器中有一个改进票 ( CORE-2332 ) 用于此，但尚未计划用于版本。此票证还包含解决方法的示例：

WITH EDU_EPT AS (
  SELECT EEPT2.TARGET_SWE
  FROM EDUCATION_EVENT_PR_TRGT EEPT2
  WHERE EEPT2.EDUCATION_EVENT_ID = :EDU_EVENT_ID
  ORDER BY EEPT2.ORDINAL, EEPT2.ID
)
SELECT LIST('• ' || EEPT.TARGET_SWE, ASCII_CHAR(13) || ASCII_CHAR(10)) || '.'
FROM EDU_EPT EEPT
于 2013-06-24T18:07:40.690 回答
-1

我已经为客户实现了一个带有 JSON 的解决方案。也许这可以帮助某人。

select 
...
sales.customer,
cast (list('{productId="' || salesproduct.productId || 
'", productPrice="' || salesproduct.productPrice  ||
'", productQt="' || salesproduct.productQt ||'"}') as varchar(800) ) Sales_Json
from sales inner join salesproduct on ...
group by salesproduct.customer
于 2021-12-04T16:46:45.127 回答