我正在使用 WSS4J 在已形成的 SOAP 请求信封的标头中添加用户名令牌。
下面是 SOAP 请求的样子:
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://sample03.samples.rampart.apache.org/xsd">
<soapenv:Header/>
<soapenv:Body>
<xsd:echo>
<xsd:param0>hurro kitty</xsd:param0>
</xsd:echo>
</soapenv:Body></soapenv:Envelope>
这是我的代码(字符串,请求,是上面的请求):
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
InputSource inStream = new InputSource();
inStream.setCharacterStream(new StringReader(request));
Document document = builder.parse(inStream);
WSSecUsernameToken usernametoken = new WSSecUsernameToken();
usernametoken.setPasswordType(WSConstants.PASSWORD_TEXT);
usernametoken.setUserInfo(username, password);
WSSecHeader secHeader = new WSSecHeader("", false);
secHeader.insertSecurityHeader(document);
usernametoken.build(document, secHeader);
这是我的结果(注意插入的标头命名空间不正确,并且有两个标头):
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://sample03.samples.rampart.apache.org/xsd">
<Header>
<wsse:Security soapenv:mustUnderstand="1" xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd">
<wsse:UsernameToken wsu:Id="UsernameToken-2765109" xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd">
<wsse:Username>bob</wsse:Username>
<wsse:Password Type="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordText">bobPW</wsse:Password>
</wsse:UsernameToken>
</wsse:Security>
</Header>
<soapenv:Header/>
<soapenv:Body>
<xsd:echo>
<xsd:param0>hurro kitty</xsd:param0>
</xsd:echo>
</soapenv:Body></soapenv:Envelope>
我究竟做错了什么?