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我有一个表情cos(phi) + sin(phi)。x+y假设cos(phi) is x, 和,我如何将这个表达式转换为最大值sin(phi) is y?
cos(phi) + sin(phi)
x+y
cos(phi) is x
sin(phi) is y
expr: cos(phi) + sin(phi); subst([cos(phi)=x, sin(phi)=y], expr);
要不就
(%i1) cos(phi) + sin(phi), cos(phi) = x, sin(phi) = y; (%o1) y + x