为了实现独特元素的可迭代,[2] 是否可以接受?
# [1]
if element not in list:
list.append(element)
# [2]
dict[element] = None # value doesn't matter
为了实现独特元素的可迭代,[2] 是否可以接受?
# [1]
if element not in list:
list.append(element)
# [2]
dict[element] = None # value doesn't matter