7

我是一个非常新的 Python

如果有重复的单词,我想换句。

正确的

  • 前任。“这真是太好了”->“这真是太好了”
  • 前任。“这就是就是”-->“这就是”

现在我正在使用这个 reg。但它确实在字母上发生了变化。前任。“我和我的朋友很高兴”->“我和我的朋友很高兴”(它删除了“i”和空格)错误

text = re.sub(r'(\w+)\1', r'\1', text) #remove duplicated words in row

我怎样才能做同样的改变,但它必须检查单词而不是字母?

4

3 回答 3

9

使用非正则表达式解决方案itertools.groupby

>>> strs = "this is just is is"
>>> from itertools import groupby
>>> " ".join([k for k,v in groupby(strs.split())])
'this is just is'
>>> strs = "this just so so so nice" 
>>> " ".join([k for k,v in groupby(strs.split())])
'this just so nice'
于 2013-06-21T15:10:34.213 回答
9
text = re.sub(r'\b(\w+)( \1\b)+', r'\1', text) #remove duplicated words in row

\b匹配空字符串,但仅在单词的开头或结尾。

于 2013-06-21T15:15:18.293 回答
0
  • \b:匹配单词边界

  • \w:任何单词字符

  • \1:用找到的第二个单词替换匹配项

      import re
    
    
      def Remove_Duplicates(Test_string):
          Pattern = r"\b(\w+)(?:\W\1\b)+"
          return re.sub(Pattern, r"\1", Test_string, flags=re.IGNORECASE)
    
    
      Test_string1 = "Good bye bye world world"
      Test_string2 = "Ram went went to to his home"
      Test_string3 = "Hello hello world world"
      print(Remove_Duplicates(Test_string1))
      print(Remove_Duplicates(Test_string2))
      print(Remove_Duplicates(Test_string3))
    

结果:

    Good bye world
    Ram went to his home
    Hello world
于 2021-02-17T19:22:46.383 回答