为了得到这个结果,你需要做一些事情:
- 取消透视当前数据
- PIVOT来自 unpivot 的结果
- 使用动态 SQL,因为您将拥有未知数量的行
由于您使用的是 SQL Server 2005+,因此您可以使用 CROSS APPLY 来取消透视数据,此过程需要您的多列item_id, color,size并将weight它们转换为多行:
select col+'_'+cast(seq as varchar(50)) col,
     value
from 
(
   select item_id as seq, item_id, color, size, weight
   from yourtable
) d
cross apply
(
   values
    ('item_id', cast(item_id as varchar(50))),
    ('color', color),
    ('size', size),
    ('weight', cast(weight as varchar(50)))
) c (col, value);
请参阅SQL Fiddle with Demo。这给出了一个结果:
|       COL |  VALUE |
----------------------
| item_id_1 |      1 |
|   color_1 |   blue |
|    size_1 |  large |
|  weight_1 |     65 |
| item_id_2 |      2 |
|   color_2 | orange |
|    size_2 |  large |
|  weight_2 |     57 |
| item_id_3 |      3 |
正如您从结果中看到的那样,您现在有多个基于原始数据的行。这些COL值是您将用于 PIVOT 的值。完整的动态 SQL 代码将类似于以下内容:
DECLARE @cols AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)
select @cols = STUFF((SELECT ',' + QUOTENAME(col+'_'+cast(item_id as varchar(10))) 
                    from yourtable
                    cross apply
                    (
                      select 'item_id', 0 union all
                      select 'color', 1 union all
                      select 'size', 2 union all
                      select 'weight', 3 
                    ) c (col, so)
                    group by item_id, col, so
                    order by item_id, so
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')
set @query = 'SELECT ' + @cols + ' 
            from 
            (
                select col+''_''+cast(seq as varchar(50)) col,
                  value
                from 
                (
                  select item_id as seq, item_id, color, size, weight
                  from yourtable
                ) d
                cross apply
                (
                  values
                    (''item_id'', cast(item_id as varchar(50))),
                    (''color'', color),
                    (''size'', size),
                    (''weight'', cast(weight as varchar(50)))
                ) c (col, value)
            ) x
            pivot 
            (
                max(value)
                for col in (' + @cols + ')
            ) p '
execute(@query);
请参阅SQL Fiddle with Demo。最终结果是:
| ITEM_ID_1 | COLOR_1 | SIZE_1 | WEIGHT_1 | ITEM_ID_2 | COLOR_2 | SIZE_2 | WEIGHT_2 | ITEM_ID_3 | COLOR_3 | SIZE_3 | WEIGHT_3 | ITEM_ID_4 | COLOR_4 | SIZE_4 | WEIGHT_4 |
-------------------------------------------------------------------------------------------------------------------------------------------------------------------------
|         1 |    blue |  large |       65 |         2 |  orange |  large |       57 |         3 |     red |  small |       12 |         4 |  violet | medium |       34 |