sql - 在特定表的每个字段中搜索 Oracle 中的值列表

Question

是否可以在特定表的每个字段中搜索 Oracle 中的值列表。要求是从表中提取与表的任何列中的列表匹配的所有详细信息。表包含大量数据，我需要提取为期 6 个月的数据

Answer 1

CREATE TABLE large_table
(
    col1 VARCHAR2(100)
,   col2 VARCHAR2(100)
,   col3 VARCHAR2(100)
,   col4 VARCHAR2(100)
,   col5 VARCHAR2(100)
);

INSERT INTO large_table VALUES ('aa', 'bb', 'cc', 'dd', 'ee');
INSERT INTO large_table VALUES ('ax', 'bx', 'cx', 'dx', 'ex');
INSERT INTO large_table VALUES ('ay', 'by', 'cy', 'dd', 'ee');

CREATE TABLE values_to_search
(
    s_value VARCHAR2(30)
);

INSERT INTO values_to_search VALUES ('aa');
INSERT INTO values_to_search VALUES ('bb');
INSERT INTO values_to_search VALUES ('cc');
INSERT INTO values_to_search VALUES ('dd');
INSERT INTO values_to_search VALUES ('ee');

SELECT  CASE WHEN EXISTS(SELECT 1 FROM values_to_search s WHERE INSTR(l.col1, s.s_value) > 0 ) THEN 1 ELSE NULL END AS s1
,       CASE WHEN EXISTS(SELECT 1 FROM values_to_search s WHERE INSTR(l.col2, s.s_value) > 0 ) THEN 1 ELSE NULL END AS s2
,       CASE WHEN EXISTS(SELECT 1 FROM values_to_search s WHERE INSTR(l.col3, s.s_value) > 0 ) THEN 1 ELSE NULL END AS s3
,       CASE WHEN EXISTS(SELECT 1 FROM values_to_search s WHERE INSTR(l.col4, s.s_value) > 0 ) THEN 1 ELSE NULL END AS s4
,       CASE WHEN EXISTS(SELECT 1 FROM values_to_search s WHERE INSTR(l.col5, s.s_value) > 0 ) THEN 1 ELSE NULL END AS s5
FROM    large_table l;
/*
1   1   1   1   1

            1   1
*/

CREATE TABLE search_result
(
    col1 VARCHAR2(100)
,   col2 VARCHAR2(100)
,   col3 VARCHAR2(100)
,   col4 VARCHAR2(100)
,   col5 VARCHAR2(100)
);

INSERT  INTO search_result
SELECT  /*+ PARALLEL */ *
FROM    large_table l
WHERE   COALESCE
        (
                CASE WHEN EXISTS(SELECT 1 FROM values_to_search s WHERE INSTR(l.col1, s.s_value) > 0 ) THEN 1 ELSE NULL END
        ,       CASE WHEN EXISTS(SELECT 1 FROM values_to_search s WHERE INSTR(l.col2, s.s_value) > 0 ) THEN 1 ELSE NULL END
        ,       CASE WHEN EXISTS(SELECT 1 FROM values_to_search s WHERE INSTR(l.col3, s.s_value) > 0 ) THEN 1 ELSE NULL END
        ,       CASE WHEN EXISTS(SELECT 1 FROM values_to_search s WHERE INSTR(l.col4, s.s_value) > 0 ) THEN 1 ELSE NULL END
        ,       CASE WHEN EXISTS(SELECT 1 FROM values_to_search s WHERE INSTR(l.col5, s.s_value) > 0 ) THEN 1 ELSE NULL END
        ) IS NOT NULL
;
-- 2 rows inserted.
/*
aa  bb  cc  dd  ee
ay  by  cy  dd  ee
*/

根据我们掌握的数量信息，没有错误的答案。

添加一些 where 条件。希望您创建了一些索引 - 这是一个很好的列。

不要扫描整个表格 - 使用日期范围并执行此操作，即：逐日或逐月。

Answer 2

I'd create a table to hold the search values

CREATE TABLE s (x VARCHAR2(30) PRIMARY KEY) ORGANIZATION INDEX;
INSERT INTO s VALUES ('x');
INSERT INTO s VALUES ('y');
INSERT INTO s VALUES ('z');
COMMIT;
EXEC DBMS_STATS.GATHER_TABLE_STATS(null, 's');

and then construct the long query to check column by column:

SELECT * FROM large_table
WHERE col1 IN (SELECT x FROM s)
   OR col2 IN (SELECT x FROM s)
   ...
   OR colx IN (SELECT x FROM s);

If the number of columns is huge, I'd use SQL to help writing the query:

SELECT 'OR '||column_name||' IN (SELECT x FROM s)' AS line
  FROM user_tab_columns 
 WHERE table_name = 'large_table';