sql-server-2008 - 排列具有数字值和连字符值的列

Question

我正在尝试排列具有以下值的列：

6-3
11-1
3
8-5
5
6-2
1
7
11-4
8-12
2

我希望它们像这样排列：

1
2
3
5
7
6-2
6-3
8-5
8-12
11-1
11-4

我现在有这个查询：

select column_name from database_name.dbo.table_name
order by
(case when (BOX_NO not like '%-%')
then -1 when (BOX_NO like '%-%')
then cast(SUBSTRING(reverse(BOX_NO), LEN(BOX_NO)-(CHARINDEX('-', reverse(BOX_NO))-2), 0) as int) end),
(case when (column_name not like '%-%')
then cast(column_name as int)
when (column_name like '%-%')
then cast(SUBSTRING(column_name, LEN(column_name)-(CHARINDEX('-', reverse(column_name))-2), 8000) as int) end)

我要疯了。如果有人可以帮助我，那就太好了。谢谢！

Answer 1

declare @test table ( value varchar(10))

insert @test values ('6-3'),
    ('11-1'),
    ('3'),
    ('8-5'),
    ('5'),
    ('6-2'),
    ('1'),
    ('7'),
    ('11-4'),
    ('8-12'),
    ('2')

select 
    T2.value,
    case when CHARINDEX('-', T1.value) = 0 then cast(T1.value as int) else cast(LEFT(T1.value, CHARINDEX('-', T1.value) - 1) as int) end,
    case when CHARINDEX('-', T1.value) = 0 then 0 else cast(substring(T1.value, CHARINDEX('-', T1.value) + 1, 10) as int) end
from @test T1, @test T2
where T1.value = T2.value
order by 2, 3

Answer 2

小雏菊！现在一切都很好。第一个案例是错误的。不应该有第二次逆转。搜索应该从 8000 开始，而不是 0。我的错！

(case when (column_name not like '%-%') then 0 when (column_name like '%-%') then cast(SUBSTRING(reverse(column_name), LEN(column_name)-(CHARINDEX('-', column_name)-2), 8000) as int) end),