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为了清楚起见，我创建了一个要点，其中包含我所指的数据格式的示例：

https://gist.github.com/TestAcc7777/5823760

在一些其他不相关的数据之后，输出文件包含许多这样的表格块，一个接一个，标题部分每次都重复。每个标题实例最多有八组读数，它们一起组成一个块。标题中数量的组织反映了后续读数的值的组织。

鉴于此，我需要提取标题中给出的一些数量的值，将它们与其关联的数量放在一个文件中，并让 matplotlib 绘制一组数量与另一组数量。例如 eng_tot 与时间 (ps)。

我完全迷失了，因为这远远超出了我使用 Python 或 matplotlib 的经验，所以欢迎任何帮助。

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1 回答 1

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这不是一个完整的答案，但它应该让你开始。

#!/bin/env python

import sys
import re
import pprint

# Some function that determines whether a line is a seperator
def is_sep(line):
    return (line.count('-') > 80)

# Some function that parses the "block"
def parse_block(lines):
    parsed_lines = []
    for line in lines:
        matches = re.findall('(\S+)', line)
        parsed_lines.append(matches)
    return parsed_lines

if __name__ == "__main__":
    # Read in data
    with open('data.txt', 'r') as fh:
        data = fh.read()

    # Split data into lines, then split the lines into "blocks"
    blocks = []
    block_lines = []
    for line in data.splitlines():
        if(is_sep(line)):
            blocks.append(block_lines)
            block_lines = []
        else:
            block_lines.append(line)

    # This splitting method will create an empty "block" as the first element of the list, delete it
    blocks = blocks[1:]

    # For all blocks but the header block, pass it to "parse_block"
    parsed_blocks = []
    for block in blocks[1:]:
        parsed_blocks.append(parse_block(block))

    pprint.pprint(parsed_blocks[0])

例如，您的数据的最后一个块将被解析为：

[['1', '2.6814E+03', '3.3117E+02', '1.6616E+03', '-1.1814E+02', '1.8312E+03', '3.5247E+03', '2.5879E+02', '-3.8350E+03', '0.0000E+00'],
 ['0.0', '2.5785E+04', '6.8687E+01', '-6.7273E+04', '-7.6310E+03', '-1.8316E+03', '-5.7811E+04', '0.0000E+00', '0.0000E+00', '0.0000E+00'],
 ['4.9', '1.3300E+04', '0.0000E+00', '0.0000E+00', '0.0000E+00', '9.0000E+01', '9.0000E+01', '9.0000E+01', '0.0000E+00', '1.1911E+02'],
 [],
 ['rolling', '2.6814E+03', '3.3117E+02', '1.6616E+03', '-1.1814E+02', '1.8312E+03', '3.5247E+03', '2.5879E+02', '-3.8350E+03', '0.0000E+00'],
 ['averages', '2.5785E+04', '6.8687E+01', '-6.7273E+04', '-7.6310E+03', '-1.8316E+03', '-5.7811E+04', '0.0000E+00', '0.0000E+00', '0.0000E+00'],
 ['1.3300E+04', '0.0000E+00', '0.0000E+00', '0.0000E+00', '9.0000E+01', '9.0000E+01', '9.0000E+01', '0.0000E+00', '1.1911E+02']]
于 2013-06-20T16:41:41.527 回答