arrays - 如果数组中包含某些字符串，则从数组中删除元素

Question

假设我有一个包含以下数据的数组：

@array[0] = "hello this is a text"
@array[1] = "this is a cat" 
@array[2] = "this is a dog"
@array[3] = "this is a person"
@array[4] = "this is a computer"
@array[5] = "this is a code"
@array[6] = "this is an array"
@array[7] = "this is an element"
@array[8] = "this is a number"

我想要一个循环，它遍历所有数组元素，如果元素确实有狗，则找出其中是否有任何元素具有值“狗”，然后删除该元素。所以结果是：

@array[0] = "hello this is a text"
@array[1] = "this is a cat" 
@array[2] = "this is a person"
@array[3] = "this is a computer"
@array[4] = "this is a code"
@array[5] = "this is an array"
@array[6] = "this is an element"
@array[7] = "this is a number"

Answer 1

@array = grep not /dog/, @array;

@array = grep !/dog/, @array;

Answer 2

显然，重新分配整个数组更容易，但要真正循环并删除，你可以这样做：

use strict;
use warnings;

my @array = (
    'hello this is a text',
    'this is a cat',
    'this is a dog',
    'this is a person',
    'this is a computer',
    'this is a code',
    'this is an array',
    'this is an element',
    'this is a number'
);

for my $index (reverse 0..$#array) {
    if ( $array[$index] =~ /dog/ ) {
        splice(@array, $index, 1, ());
    }
}

print "$_\n" for @array;

输出：

hello this is a text
this is a cat
this is a person
this is a computer
this is a code
this is an array
this is an element
this is a number

Answer 3

@array = grep(!/dog/, @array);